a) Suppose that in 1000 memory references there are 40 misses in L1 cache and 10 misses in L2 cache. If the miss penalty of L2 is 200 clock cycles, hit time of L1 is 1 clock cycle, and hit time of L2 is 15 clock cycles, Find the average memory access time in clock cycles.
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- If memory read cycle takes 100 ns and a cache read cycle takes 20 ns, then for four continuous references, the first one brings the main memory contents to cache and the next three from cache. Find the time taken for the Read cycle with and without Cache? What is the Percentage speedup obtained?Given that a 4-way set associative cache memory has 64 KB data and each block contains 32 bytes. The main memory capacity is 4 GB. a. Find the number of bits for the main memory address. ANSWER: b. How many blocks are there in a set? ANSWER: c. How many sets the cache has? ANSWER: d. The main memory address format is => | Tag: bits | blocks sets bits | Set: e. Which set will be mapped by the main memory address 458195h. ANSWER: decimal) bits bits | Word: (inSuppose that in 1000 memory references there are 50 misses in the first-level cache, 20 misses in the second-level cache, and 5 misses in the third-level cache. Assume the miss penalty from the L3 cache to memory is 100 clock cycle, the hit time of the L3 cache is 10 clocks, the hit time of the L2 cache is 4 clocks, the hit time of L1 is 1 clock cycle. What is the average memory access time?
- A CPU has 32-bit memory address and a 256 KB cache memory. The cache is organized as a 4-way set associative cache with cache block size of 16 bytes. a. What is the number of sets in the cache? b. What is the size (in bits) of the tag field per cache block? c. What is the number and size of comparators required for tag matching? d. How many address bits are required to find the byte offset within a cache block? e. What is the total amount of extra memory (in bytes) required for the tag bits?Suppose a byte-addressable computer using set-associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes.Q.) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache?The memory access time is I nanosecond for read operation with a hit in cache. * nanoseconds for a read operation with a miss in cache, 2 nanoseconds for a write operation with a hit in cache and 10 anoseconds for a write operation with a miss in cache. Execution of a sequence of instructions involves 100 instruction fetch operations, 60 memory operand read operations and 40 memory operand write operations. The cache hit-ratio is 0.9. The average memory access time (in nanoseconds) in executing the sequence of instructions is
- 3. The table below represents five lines from a cache that uses fully associative mapping with a block size of 8. Identify the address of the shaded data, 0xE6, first in binary and then in hexadecimal. The tag numbers and word id bits are in binary, but the content of the cache (the data) is in hexadecimal. Word id bits Tag 000 001 010 011 100 101 110 111 ------------------------------------------ 1011010 10 65 BA 0F C4 19 6E C3 1100101 21 76 CB 80 D5 2A 7F B5 0011011 32 87 DC 91 E6 3B F0 A6 1100000 43 98 ED A2 F7 4C E1 97 1111100 54 9A FE B3 08 5D D2 88CO. A certain processor uses a fully associative cache of size 16 kB. The cache block size is 16 bytes. Assume that the main memory is byte addressable and uses a 32-bit address. How many bits are required for the Tag and the Index ticlds respectively in the addresses generated by the processor?Consider a single-level cache with an access time of 5 ns, a block size of 128 bytes and a hit ratio H = 0.95. Main memory uses a block transfer capability that has a first-word (8 bytes) access time of 100 ns and an access time of 10 ns for each word thereafter. A.What is the access time when there is a cache miss? Assume that the cache waits until the line has been fetched from main memory and re-executes for a hit. B.Suppose that increasing the block size to 256 bytes increases H to 0.97. Does this reduce the average memory access time?
- Suppose a byte-addressable computer using set associative cache has 2^24 bytes of main memory and a cache size of 64K bytes, and each cache block contains 32 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache?Suppose a byte-addressable computer using set associative cache has 8M byes of main memory and a cache of 128 blocks, where each cache block contains 64 bytes. a) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 16-way set associative, what is the format of a memory address as seen by the cacheSuppose a byte-addressable computer using set-associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes.Q.) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?