A student prepared three nickel samples in the lab but forgot to label them. The samples that were prepared were [Ni(H₂O)6]2+, [Ni(NH3)612+, and [Ni(H₂NCH₂CH₂NH2)312+. The sample vials were coloured violet, blue, and green. Which sample corresponded to which coloured vial? O [Ni(H2O)%]2+ = green; [Ni(NH3)%]2+ = blue; [Ni(H2NCH,CH,NH2)3]2+ = violet O [Ni(H2O)%]2+ = violet; [Ni(NH3)%]2+ = green; [Ni(H2NCH,CH,NH2)3]2+ = blue [Ni(H2O)%]2+ = violet; [Ni(NH3)%]2+ = blue; [Ni(H2NCH2CH,NH2)3]2+ = green [Ni(H,O)%]2+ = green; [Ni(NH3)%]2+ = violet; [Ni(H,NCH,CH,NH2)3]2+ = blue O [Ni(H2O)%]2+ = blue; [Ni(NH3)%]2+ = green; [Ni(H,NCH,CH,NH,\3]2+ = violet

Chemistry: An Atoms First Approach
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Chapter20: Transition Metals And Coordination Chemistry
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A student prepared three nickel samples in the lab but forgot to label them. The
samples that were prepared were [Ni(H₂O)6]2+, [Ni(NH3)612+, and
[Ni(H₂NCH₂CH₂NH₂)3]2+. The sample vials were coloured violet, blue, and green.
Which sample corresponded to which coloured vial?
O
[Ni(H₂O)6]2+ = green; [Ni(NH3)6]2+ = blue; [Ni(H₂NCH₂CH₂NH2)3]²+ = violet
O
[Ni(H₂O)6]2+ = violet; [Ni(NH3)%]2+ = green; [Ni(H,NCH,CH,NH,)3]2+ = blue
O
[Ni(H2O)%]2+ = violet; [Ni(NH3)%]2+ = blue; [Ni(H,NCH,CH,NH2)3]2+ = green
O
[Ni(H2O)%]2+ = green; [Ni(NH3)]2+ = violet; [Ni(H2NCH,CH,NH,)3]2+ = blue
O [Ni(H,O),]2+ = blue; [Ni(NH3)%]2+ = green; [Ni(H,NCH,CH,NH2)2+ = violet
Transcribed Image Text:A student prepared three nickel samples in the lab but forgot to label them. The samples that were prepared were [Ni(H₂O)6]2+, [Ni(NH3)612+, and [Ni(H₂NCH₂CH₂NH₂)3]2+. The sample vials were coloured violet, blue, and green. Which sample corresponded to which coloured vial? O [Ni(H₂O)6]2+ = green; [Ni(NH3)6]2+ = blue; [Ni(H₂NCH₂CH₂NH2)3]²+ = violet O [Ni(H₂O)6]2+ = violet; [Ni(NH3)%]2+ = green; [Ni(H,NCH,CH,NH,)3]2+ = blue O [Ni(H2O)%]2+ = violet; [Ni(NH3)%]2+ = blue; [Ni(H,NCH,CH,NH2)3]2+ = green O [Ni(H2O)%]2+ = green; [Ni(NH3)]2+ = violet; [Ni(H2NCH,CH,NH,)3]2+ = blue O [Ni(H,O),]2+ = blue; [Ni(NH3)%]2+ = green; [Ni(H,NCH,CH,NH2)2+ = violet
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