A steel har 900 mm long. Its two ends are 40 mm and 30 mm in diameter and the length of each rod is 200 mm. The middle portion of the bar is 15 mm in diameter and 500 mm long. If the bar is subjected an axial tensile load of 15 kN, determine (1) Stress in each section, (2) Total extension. [Take E= 200 x 10³ N/mm²]. Given: D₁ = 40 mm; D₂ = 15 mm; D3 = 30 mm; L₁ = 200 mm; L₂ = 500 mm; L3 - 200 mm. P = 15 kN = 15 x 103 N; E= 200 × 10³ N/mm².

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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A steel har 900 mm long. Its two ends
are 40 mm and 30 mm in diameter and the length of each rod
is 200 mm. The middle portion of the bar is 15 mm in
diameter and 500 mm long. If the bar is subjected an axial
tensile load of 15 kN, determine (1) Stress in each section,
(2) Total extension.
[Take E= 200 x 10³ N/mm²].
Given: D₁ = 40 mm; D₂ = 15 mm; D3 = 30 mm;
L₂ = 500 mm; L 200 mm.
L₁ = 200 mm;
P = 15 kN = 15 x 103 N;
=
E = 200 × 10³ N/mm².
15 KN
To find:
D₁ = 40 mm
D₂ - 15 mm
200 mm 500 mm f
D₂ - 30 mm
200 mm
(1) Stress in each section, and
(2) Total extension.
15 KN
Transcribed Image Text:A steel har 900 mm long. Its two ends are 40 mm and 30 mm in diameter and the length of each rod is 200 mm. The middle portion of the bar is 15 mm in diameter and 500 mm long. If the bar is subjected an axial tensile load of 15 kN, determine (1) Stress in each section, (2) Total extension. [Take E= 200 x 10³ N/mm²]. Given: D₁ = 40 mm; D₂ = 15 mm; D3 = 30 mm; L₂ = 500 mm; L 200 mm. L₁ = 200 mm; P = 15 kN = 15 x 103 N; = E = 200 × 10³ N/mm². 15 KN To find: D₁ = 40 mm D₂ - 15 mm 200 mm 500 mm f D₂ - 30 mm 200 mm (1) Stress in each section, and (2) Total extension. 15 KN
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