A solution of HCI is standardized against a sample which has been previously found to contain 71.22% Na2CO3, and no other basic material. The sample weighing 0.5962 g is treated with 32.7 mL of the acid and the excess acid then requires 1.52 mL of NaOH solution. If 1.00 mL of the acid is equivalent to 0.9690 mL of the NaOH, calculate for the normality of each solution.

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Chapter9: Acids, Bases, And Salts
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A solution of HCI is standardized against a sample which has been previously found to contain
71.22% Na2CO3, and no other basic material. The sample weighing 0.5962 g is treated with
32.7 mL of the acid and the excess acid then requires 1.52 mL of NaOH solution. If 1.00 mL of
the acid is equivalent to 0.9690 mL of the NaOH, calculate for the normality of each solution.
Transcribed Image Text:A solution of HCI is standardized against a sample which has been previously found to contain 71.22% Na2CO3, and no other basic material. The sample weighing 0.5962 g is treated with 32.7 mL of the acid and the excess acid then requires 1.52 mL of NaOH solution. If 1.00 mL of the acid is equivalent to 0.9690 mL of the NaOH, calculate for the normality of each solution.
Normality of HCI *
5.1074
0.2573
0.1287
2.5537
Normality of NaOH *
5.2708
0.2656
0.1328
2.6354
Transcribed Image Text:Normality of HCI * 5.1074 0.2573 0.1287 2.5537 Normality of NaOH * 5.2708 0.2656 0.1328 2.6354
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