A solution is made by the following steps. 1. 90.0 mg ± 0.2 mg of dye with molar mass 685.79 g/mol ± 0.02 g/mol is dissolved in a 100.00 mL ± 0.05 mL volumetric flask with water to make solution #1. 2. 25.00 mL of solution 1 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #2. 3. 25.00 mL of solution 2 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #3. A.) If you have available a 5.00 mL ± 0.01 mL, 10.00 mL ± 0.05 mL, and 25.00 mL± 0.15 mL. Describe how to use the pipettes and the directions above to make the most precise solution
A solution is made by the following steps. 1. 90.0 mg ± 0.2 mg of dye with molar mass 685.79 g/mol ± 0.02 g/mol is dissolved in a 100.00 mL ± 0.05 mL volumetric flask with water to make solution #1. 2. 25.00 mL of solution 1 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #2. 3. 25.00 mL of solution 2 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #3. A.) If you have available a 5.00 mL ± 0.01 mL, 10.00 mL ± 0.05 mL, and 25.00 mL± 0.15 mL. Describe how to use the pipettes and the directions above to make the most precise solution
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.107QE
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A solution is made by the following steps.
1. 90.0 mg ± 0.2 mg of dye with molar mass 685.79 g/mol ± 0.02 g/mol is dissolved in a 100.00 mL ± 0.05 mL volumetric flask with water to make solution #1.
2. 25.00 mL of solution 1 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #2.
3. 25.00 mL of solution 2 is added 100.00 mL ± 0.05 mL volumetric flask with water to make solution #3.
A.) If you have available a 5.00 mL ± 0.01 mL, 10.00 mL ± 0.05 mL, and 25.00 mL± 0.15 mL. Describe how to use the pipettes and the directions above to make the most precise solution #3. Explain why this is the most precise method.
B.) Determine the concentration ± absolute error of solution #3 in molarity. Explain the calculations you needed to do.
C.) Using Beer's law (10% error), solution #3 is found to be 2.0 ✕ 10-5 M. Was solution #3 likely made within the expected error. Explain.
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