A solid sphere of mass M = 10.0 kg and radius r = 0.10 m with uniform density rolls on a horizontal surface as shown in Fig. 4. The sphere's the center of mass (CM) is moving initially at v = 17.8 m/s. Assume that there are no losses of energy due to friction. Eventually the sphere reaches the highest point of height h on the slope. What is the value of h in m? Keep three significant figures for the answer. The moment of inertia of a sphere of radius r and mass M is (2/5)Mr2.g = 9.80 m/s.

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Fig. 4
Transcribed Image Text:30° Fig. 4
A solid sphere of mass M = 10.0 kg and radius r = 0.10 m with uniform density rolls on a horizontal surface as shown in Fig. 4. The sphere's
the center of mass (CM) is moving initially at v = 17.8 m/s. Assume that there are no losses of energy due to friction. Eventually the sphere
reaches the highest point of height h on the slope. What is the value of h in m? Keep three significant figures for the answer. The moment of
inertia of a sphere of radius r and mass M is (2/5)Mr2.g = 9.80 m/s.
Transcribed Image Text:A solid sphere of mass M = 10.0 kg and radius r = 0.10 m with uniform density rolls on a horizontal surface as shown in Fig. 4. The sphere's the center of mass (CM) is moving initially at v = 17.8 m/s. Assume that there are no losses of energy due to friction. Eventually the sphere reaches the highest point of height h on the slope. What is the value of h in m? Keep three significant figures for the answer. The moment of inertia of a sphere of radius r and mass M is (2/5)Mr2.g = 9.80 m/s.
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