A simply supported beam made of five 50mm x 200mm blocks of wood carries the load as shown in the figure. Determine the allowable pitch of the bolts if each bolt can resist 3 kN force.
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Subject: STRENGTH OF MATERIALS (Civil Engineering)
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- O 88 130% v - + I Annotate T| Edit Trial expired Unlock Full Version ENGR 263 + A A A T O 4.10 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is an overhanging beam that supports a uniformly distributed roof load of 500 lb/ft. It also carries concentrated loads from a rooftop HVAC unit (4000 lb), an interior hanging display support (2000 lb), and a marquee sign (3000 lb). Marquee overnang Displau SLIPPort II Raof Kiots Ol I W = 500 Ib/Ft A B 4000 b 2000 000 I Steel beam !! I1 3 FE 5 FE - Ft RoOFtop HVAC unit 10 FE 4 Ft Marquee sign< R R2 Steel beam (negligible weight) Free-body diagram Dispiay Support Loading condition5) Calculate P the allowable tensile load for the butt joint shown. Each A325-N high-strength bolt has a diameter of 0.9 inches. The plates are made of ASTM A36 steel. If the applied load is 200 kips, is this connection adequate? If not, what needs to be changed so that this connection can handle an applied load of 200 kips? P- ФФ P ! 12"x " P. P.A bolted connection shown consists of an angular section L 150mmx100mm x8mm. Bolt diameter = 18mm. Determine the effective net area of the section. (Ae). Properties of an L150x100x8: Area = 1,894 mm2 Fy = 248 MPa Fu = 400 MPa x = 23 mm y = 48 mm 50 50 50 50 50 50 150 40 www.AwNNO 60 100 50 P
- The connection shown is subjected to a tensile force of P = 100 kN. The allowable shear stress for the bolts is 100 MPa. Assume each bolt supports an equal portion of the load. Determine the required diameter of the bolts. a. 20.6 mm b. 25.2 mm c.35.7 mm d.17.8 mm choose letter of correct answerThe built-up section shown below is fastened together by passing two 10 mm diameter rivets through the top and bottom plates into the flanges of the beam. Each rivet will withstand 11.8 kN in shear. Determine the required spacing of the rivets along the length of the beam if it carries a shearing force of 199 kN. 12 mm x 180 mm plates (2) I IPE I 400x180x642.2 steel 10 mm rivetsA bolted connection shown is made up of 2L150 x 100 x 9.5 mm. The angle is made of A-36 steel and the bolts have diameter of 22 mm. Properties of 2L150 x 100 x 9.5 mm: A = 4660 mm2 t = 9.5 mm Fy = 248 MPa Fu = 400 MPa Properties of 20 mm A-325 bolts: Fu = 400 MPa 50 50 50 50 50 50,50 힝힝이어 Gusset Plate 9.5mm 100mm Gusset Plate 100mm 31.25 62.5 T 56.25 a. Nominal dimension of hole diameter, dn = 25 mm b. Determine the ultimate shear capacity (kN) of the connection. c. Determine the ultimate tearing capacity (kN) of the connection if the shear lag factor, U = 0.75.
- Question 17 2L5x3x7mm tension momber is connocted to a gussot plate by 16-mm-diameter bolts as shown in the figure, Given that e= 30 mm, s= 50 mm, Fy =345 MPa and Fu=402 MPa, caicukato the following 2 L5 x3x % LLBD (two angles, long legs back-to-back) A242 stoel 60 mm e (am) (mn) e (mm) 55 Not area in shoar for a single angle under block shear lailue, Ariv mm? 56. Not area in tension for a single anglo under.block shoar failuto Arit = 57. Norninal block shear strongth in kN of the double angle Use Ups 10, Pn INPUT ALL ANSWERS AS WHOLE NUMBERBolted and Riveted Connections From the bolted connection shown, the diameter of bolts is 18mm0 with the hole diameter equal to 3mm bigger than the bolt, the angular section is 100 x 75 x 8 mm, with an area of 1340 mm2. Thickness of the gusset plate is 9mm. The gusset plate and angle arc A36 steel with Fy = 250 MPa and Fu = 400 MPa. Determine the tensile capacity of the connection based on gross area. Determine the tensile capacity of the connection based on effective net area using a reduction factor of 0.85. Determine the tensile capacity of the connection based on gross area.Question 1 A 150x150×12 Equal Angle section is connected to a 12-mm thick plate using 3 M12 bolts. The angle section and the steel plate are both of Grade 300 steel. Determine the design tensile capacity of the connection while ignoring the bolt capacity. Note: 12-mm bolts require 14-mm bolt holes. P ↑ 30 30 30 30 tto ato → I 50 40 Figure 1 120 a
- Situation 8: For the connection shown in the figure. Pu = 80 KN, x1 = 200, x2 = 100, y1 = 50, y2 = y3 =y4 = 100 O 11 KN O 8 KN O 10 KN y1 y2 O 9.0 KN y3 y4 0000 1. Which of the following nearly gives the maximum force in the bolt due to the load alone? x1 0000 x2A flanged bolt coupling consists of 6 - 12 mm - diameter bolts on a bolt circle of 320 mm in diameter. Compute the number of additional 10 mm - diameter bolts on a bolt circle 200 mm in diameter to increase the torque capacity to 7.65 kNm. The shearing stress of the bolts should not exceed 60 MPa. Select one: O a. 6 bolts O b. 4 bolts O c. 3 bolts O d. 2 bolts NEXT PAGEProblem 6: Assume that the pieces making up the connection are adequate, and very stiff such that prying forces can be disregarded, and that the nominal tensile stresses on the M20-F2280 bolts govern. The service load shown consists of 25% dead load and 75% live load. Use LRFD. 1 || T = 620 kN Calculate the factored load applied to the connection shown. Calculate the nominal tensile strength of one bolt. How many bolts are required to resist the load? I I I T = 620 kN