A railroad cart with a mass of m₁ = 12.6 t is at rest at the top of an h = 10.3 m high hump yard hill. m m₂ h After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of m₂ = 18.6 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter7: Conservation Of Energy
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A railroad cart with a mass of m₁ = 12.6 t is at rest at the top of an h = 10.3 m high hump yard hill.
m
m₂
h
After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of
m₂ = 18.6 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses
due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)
Transcribed Image Text:A railroad cart with a mass of m₁ = 12.6 t is at rest at the top of an h = 10.3 m high hump yard hill. m m₂ h After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of m₂ = 18.6 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)
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