Can you please check my calculations. a) R = 100ΚΩ+47ΚΩ= 147ΚΩC = CT=XC =1110.01μF 0.0022μF12nfСT+1.8μF12π(100Hz)(1.8μF)-=884 ΩZ=R-jXc = 147KN – 884N = 147kQ<0.344° 50/0° Vf= 100 Hz(a)C₁C₂R₁www100 kn 0.01 μF 0.022 μFR₂47 ΚΩ

Answered: Image /qna-images/answer/d6b5b421-7caf-4173-8b3b-592ba17047c4.jpg

Answered: a) R = 100ΚΩ+47ΚΩ= C=Cy 1 2πfCr XC = -…

a) R = 100ΚΩ+47ΚΩ= C=Cy 1 2πfCr XC = - 1 147ΚΩ 1 1 + 0.01μFT 0.0022 F 1.8μF 1 Σπ(100Hz)(1.8μF) -=884 Ω Z= R – jXc = 147ΚΩ – 884Ω = 147ΚΩ<0.344°

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

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Can you please check my calculations.

a) R = 100ΚΩ+47ΚΩ= 147ΚΩ
C = CT=
XC =
1
1
1
0.01μF 0.0022μF
1
2nfСT
+
1.8μF
1
2π(100Hz)(1.8μF)
-=884 Ω
Z=R-jXc = 147KN – 884N = 147kQ<0.344°

50/0° V
f= 100 Hz
(a)
C₁
C₂
R₁
www
100 kn 0.01 μF 0.022 μF
R₂
47 ΚΩ

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