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A programmer is asked to translate the following HLL code into MIPS Assembly language int isa() = (10,20,30,-5,-15,40,50,-88,19,-33); string hud="***": for (int k=0;k<10;k++) isa(k)=4*isa(k); for (int k=0;k<10;k++) cout << isa(k) << hud; // print value return 0; The programmer asked you to help him complete the missing 10 statements in the MIPS code. In your answers, please separate the opcode and the operands by ONE space only as follows: sub St9,st8,St5 .data isa: word 10,20,30,-5,-15,40,50,-88,19,-33 hud: asciiz "***" .text -globl bonus bonus: Blank 1 li $t1,10 next: Iw St9,0(St0) Blank 2 Blank 3 addi St0, St0,4 Blank 4 Blank 5 la $t0, isa Blank 6 Go: Iw $a0,0(St0) Blank 7 syscall la sa0,hud li sv0,4 syscall Blank 8 Blank 9 Blank 10 li $v0,10 # exit program syscall

A programmer is asked to translate the following HLL code into MIPS Assembly language int isa() = (10,20,30,-5,-15,40,50,-88,19,-33); string hud="***": for (int k=0;k<10;k++) isa(k)=4*isa(k); for (int k=0;k<10;k++) cout << isa(k) << hud; // print value return 0; The programmer asked you to help him complete the missing 10 statements in the MIPS code. In your answers, please separate the opcode and the operands by ONE space only as follows: sub St9,st8,St5 .data isa: word 10,20,30,-5,-15,40,50,-88,19,-33 hud: asciiz "***" .text -globl bonus bonus: Blank 1 li $t1,10 next: Iw St9,0(St0) Blank 2 Blank 3 addi St0, St0,4 Blank 4 Blank 5 la $t0, isa Blank 6 Go: Iw $a0,0(St0) Blank 7 syscall la sa0,hud li sv0,4 syscall Blank 8 Blank 9 Blank 10 li $v0,10 # exit program syscall

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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A programmer is asked to translate the following HLL code into MIPS Assembly language int isa()= (10,20,30,-5,-15,40,50,-88,19,-33); string hud="***"; for (int k=0;k<10;k++) isa(k)=4*isa(k); for (int k=0;k<10;k++) cout << isa(k) << hud; // print value return 0; The programmer asked you to help him complete the missing 10 statements in the MIPS code. In your answers, please separate the opcode and the operands by ONE space only as follows: sub $t9,st8,St5 .data isa: word 10,20,30,-5,-15,40,50,-88,19,-33 hud: asciiz "***" .text globl bonus bonus: Blank 1 li $t1,10 next: Iw St9,0(St0) Blank 2 Blank 3 addi St0,St0,4 Blank 4 Blank 5 la sto, isa Blank 6 Go: Iw $a0,0(St0) Blank 7 syscall la sa0,hud li sv0,4 syscall Blank 8 Blank 9 Blank 10 li $v0,10 # exit program syscall
Transcribed Image Text:A programmer is asked to translate the following HLL code into MIPS Assembly language int isa()= (10,20,30,-5,-15,40,50,-88,19,-33); string hud="***"; for (int k=0;k<10;k++) isa(k)=4*isa(k); for (int k=0;k<10;k++) cout << isa(k) << hud; // print value return 0; The programmer asked you to help him complete the missing 10 statements in the MIPS code. In your answers, please separate the opcode and the operands by ONE space only as follows: sub $t9,st8,St5 .data isa: word 10,20,30,-5,-15,40,50,-88,19,-33 hud: asciiz "***" .text globl bonus bonus: Blank 1 li $t1,10 next: Iw St9,0(St0) Blank 2 Blank 3 addi St0,St0,4 Blank 4 Blank 5 la sto, isa Blank 6 Go: Iw $a0,0(St0) Blank 7 syscall la sa0,hud li sv0,4 syscall Blank 8 Blank 9 Blank 10 li $v0,10 # exit program syscall
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