A pole OA is subjected to two forces FAB and FAC. The force in cable AB is 3.5 KN. Given FAC = 0.948)-2.844k (KN) 4 m B A 2m 4m 6m 5 The force FAB (KN) as a vector is represented as The projection of FAC along AB in KN is The angle between AB and AC is 44.87 34.46 51.04 37.65 1.098i+ 0.274j-1.648k 0.842i+ 0.561j-2.064k| 0.8421-0.561j-2.064k 1.921i+ 0.48j-2.884k 2473 2.017 1.434 1.856 27

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter1: Introduction To Statics
Section: Chapter Questions
Problem 1.55P: The force R is the resultant of P and 0. Determine Q and the angle .
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A pole OA is subjected to two forces FAB and FAC. The force in cable AB is 3.5 KN. Given FAC -0.948)-2.844k (KN)
5m
B
2m
4m
6 m
The force FAB (KN) as a vector is represented as
The projection of FAC along AB in KN is
The angle between AB and AC is
1.098i+ 0.274j-1.648k 0.842i+ 0.561j-2.064k| 0.8421-0.561j-2.064k 1.9211+0.48j-2.884k
2.473 2.017 1.434 1.856
44.87 34.46 51.04 37.65
27
Transcribed Image Text:A pole OA is subjected to two forces FAB and FAC. The force in cable AB is 3.5 KN. Given FAC -0.948)-2.844k (KN) 5m B 2m 4m 6 m The force FAB (KN) as a vector is represented as The projection of FAC along AB in KN is The angle between AB and AC is 1.098i+ 0.274j-1.648k 0.842i+ 0.561j-2.064k| 0.8421-0.561j-2.064k 1.9211+0.48j-2.884k 2.473 2.017 1.434 1.856 44.87 34.46 51.04 37.65 27
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