A patient requires a dose of 99m-Technetium of 10 MBecquerel contained within 2 mL of injection. The administration is scheduled for 3 pm. The radiopharmacist needs to elute the 99m-Technetium from the generator at 9 am that morning, to allow time for the 99m-Technetium to bind to the carrier in the kit used. The volume of eluate required for the kit is 5 mL. A 10% excess of the eluate is always produced. How much 99m-Technetium is required to be eluted at 9 am? Express your answer as MBequerel and MBecquerel /mL

A patient requires a dose of 99m-Technetium of 10 MBecquerel contained within 2 mL of injection. The administration is scheduled for 3 pm. The radiopharmacist needs to elute the 99m-Technetium from the generator at 9 am that morning, to allow time for the 99m-Technetium to bind to the carrier in the kit used. The volume of eluate required for the kit is 5 mL. A 10% excess of the eluate is always produced. How much 99m-Technetium is required to be eluted at 9 am? Express your answer as MBequerel and MBecquerel /mL

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter32: Radiochemical Methods

Section: Chapter Questions

Problem 32.18QAP: The streptomycin in 500 g of a broth was determined by addition of 1.25 mg of the pure antibiotic...

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explain why? • Levofloxacin is a broad spectrum antibotic. It is reported that itis completely removed in an unchanged from the body and itselimination half life is 7 h. Determine the amount oflevofloxacin eliminated in urine at 10 h following IV bolusadministration of 6,25 mg/kg dose to a patient weighing 80 kg.a. 185,75 mgb. 314,25 mgc. 314,25 mg/kgd. 18,57 mg How long will it take to lose 75% of the administered doseof a drug from the body if the drug follows first orderprocess?a. 3,32 half livesb. 2,32 half livesc. 2.0 half livesd. None of the above
3.25 mL of Biomarker A (4.21 x 10-7 mol L-1) was brought up to volume with deionized water in a 50 mL volumetric flask. What is the final concentration after this dilution (in mol/ L)
A research group discovers a new version of happyase, which they call happyase*, that catalyzes the chemical reaction The researchers begin to characterize the enzyme. a)In the first experiment, with [Et] at 4 nM, they find that the Vmax is 1.6 μM s-1. Based on this experiment, what is the kcat for happyase*? (Include appropriate units.) b)In another experiment, with [Et] at 1 nM and [HAPPY] at 30 μM, the researchers find that V0300 nM s-1. What is the measured Km of happyase* for its substrate HAPPY? (Include appropriate units.) c)Further research shows that the purified happyase* used in the first two experiments wasactually contaminated with a reversible inhibitor called ANGER. When ANGER is carefully removed from the happyase* preparation, and the two experiments repeated, the measured Vmax in (a) is increased to 4.8 μM s-1, and the measured Km in (b) is now 15 μM. For the inhibitor ANGER, calculate the values of αand α’.
I(A) 1.5E-006- 1E-006- 5E-007- -0 -5E-007- -1E-006- -1.5E-006- 0 0.2 p,red = 1.9 μA Ep,red = 0.47 V 0.4 E (V) Ep,ox p,ox = 0.53 V = 1.9 μα 0.6 A An++ ne- 0.8 1 The above CV for the oxidation and reduction of a species A dissolved in 0.1 M phosphate buffer, was performed at a 3 mm diameter disc electrode with a scan rate of 0.1 V/s. Given data above, and that the diffusion coefficient (D) of A is 1 x 105 cm² s¹, answer the following questions: (d) Calculate the concentration (C) of A in Moles/L.
Bb Tangipahoa P A Classes O Thomas Willia x E THOMAS WILL O OnCourse Con x E The Spread of x A Assessment: C x G disseminate ir x b oncourseconnect.com/assessment/1651875/41774aa4-b498-clc9-30b9-e734c5204a10 O TPSS Bookmarks CHEMISTRY BENCHMARK TEST 01 CHEMISTRY I 12-3 (THOMAS WILLIAMS, ID: 12390719) 2 of 35 Each equation shows a radioactive isotope giving off some form of radiation, labeled X. Which equation suggests that an alpha particle is being emitted? yC – 4N + }X SU – Th + ;X Be + He ?C + ;x O Co + on - 9Co + X A 8 10 Ne 2 4 5 6 7 Save/Exit 1
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A research group discovers a neW version oI happyasee, which they nappyase", that catalyzes the chemical reaction HAPPY = SAD The researchers begin to characterize the enzyme. In the first experiment, with [E] at 4 nM, they find that the Vmax is 1.6 µM s-1. Based on this experiment, what is the kcat for happyase*? kcat 400 S In another experiment, with [E,] at 1 nM and [HAPPY] at 30 µM, the researchers find that Vo is equal to 300 nM s-1. What i the measured Km of happyase* for its substrate HAPPY? Km 10 x10–6 Incorrect Further research shows that the purified happyase* used in the first two experiments was actually contaminated with a reversible inhibitor called ANGER. When ANGER is carefully removed from the happyase* preparation, and the two experiments repeated, the measured Vmax increases to 4.8 µM s-, and the measured Km is now 15 µM. S For the inhibitor ANGER, calculate the values of a' and a. a' 2 Incorrect 2
l cricket LTE 7:56 PM O 79% Done Ksp for CaCO3 is 8.7 x 109. What mass of CaCO3 can dissolve in 2.50 liters of solution?
The measurement of LDH in the serum can be used to diagnose whether tissue damage hasoccurred.Students were tasked with the development of an assay for LDH activity in human serum samplesfrom a control patient (healthy) and a patient who had suffered cardiac damage. Two samples wereprovided, labelled C and D (Control and Diseased serum).The students decided to follow the loss of absorbance of NADH in an appropriate assay buffercontaining pyruvate as the substrate. Q1 (a) By examining the absorbance spectra(in the image attached) of both NAD+ and NADH below, comment why this approach is suitable strategy. Q1 (b). What would be the optimum wavelength at which they should measure absorbance? Give a reason for your answer. The students conducted the assay for LDH activity using the two serum samples. Each cuvette (path length 1 cm) contained 3ml of a suitable assay buffer (including pyruvate as substrate). 20 microlitres of either serum was added to the cuvette and the absorbance values…
60 50 40 kcal/mol 30 20 10 0 course of rx No activation energy is required OA. True OB. False •
Determine the kcat of the reaction given [E] = 2.5E-7 and the enzyme has a mass of kDa. (Km = 9.86E-6 micromol; Vmax 140.85 micromol/minute) HO.HO [S] (M) 1/[S] vo (μmol/min) 1/vo OHO (M) (μmol/min) 2.50E-06 28 4.00E+05 3.57E-02 4.00E-06 40 2.50E+05 2.50E-02 1.00E-05 70 1.00E+05 1.43E-02 2.00E-05 95 5.00E+04 1.05E-02 4.00E-05 112 2.50E+04 8.93E-03 1.00E-04 128 1.00E+04 7.81E-03 2.00E-03 139 5.00E+02 7.19E-03 1.00E-02 140 1.00E+02 7.14E-03 y = 7.0 × 10-8 x + 0.0071
PUと55UVと 15 100 f a, aud tue yues 15 increas g at avate of 201kP a /hin At what rate is the Uolume delvcasing at this instant?