#7 Solve for one mean T procedureI need help for part 4 and 5 A new process for producing synthetic gems yielded 11 stones weighing0.43 0.48 0.49 0.51 0.47 0.43 0.53 0.54 0.54 0.480.5in its first run. Summary statistics yield the sample mean 0.49 carat(s) and the sample standard deviation0.04 carat(s). Construct and interpret a 99% confidence interval for the average carat weight of syntheticgems produced by the process. You may assume that the sample is from a normal population.i. Procedure: One mean T procedureii. Assumptions: (select everything that applies)Normal populationThe number of positive and negative responses are both greater than 10✔Simple random sample✔oiii. Unknown parameter: u, population meanPopulation standard deviation is knownulation standard deviation is unknownSample size is greater than 30iv. Point estimate: sample mean, xplaces)V. Confidence levelOalso% and a =XXXand 122o Critical values: (Round the answer to 3 decimal places)left-right-Part 2 of 5carat(s) (Round the answer to 2 decimal

The question is about confidence interval.Given :Selected no. of stones ( n ) = 11Sample standard…

Answered: A new process for producing synthetic…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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#7 Solve for one mean T procedure I need help for part 4 and 5

A new process for producing synthetic gems yielded 11 stones weighing
0.43 0.48 0.49 0.51 0.47 0.43 0.53 0.54 0.54 0.48
0.5
in its first run. Summary statistics yield the sample mean 0.49 carat(s) and the sample standard deviation
0.04 carat(s). Construct and interpret a 99% confidence interval for the average carat weight of synthetic
gems produced by the process. You may assume that the sample is from a normal population.
i. Procedure: One mean T procedure
ii. Assumptions: (select everything that applies)
Normal population
The number of positive and negative responses are both greater than 10
✔Simple random sample
✔
o
iii. Unknown parameter: u, population mean
Population standard deviation is known
ulation standard deviation is unknown
Sample size is greater than 30
iv. Point estimate: sample mean, x
places)
V. Confidence level
O
also
% and a =
XXX
and 1
2
2
o Critical values: (Round the answer to 3 decimal places)
left-
right-
Part 2 of 5
carat(s) (Round the answer to 2 decimal

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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