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A mixture of 0.08069 mol of C2H4, 0.04804 mol of N2, 0.06868 mol of NH3, and 0.1210 mol of C6H6 is placed in a 1.0-L steel pressure vessel at 720 K. The following equilibrium is established: 3 C2H4(g) + 1 N2(g)  2 NH3(g) + 1 C6H6(g) At equilibrium 0.02900 mol of N2 is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C2H4, N2, NH3, and C6H6. Peq(C2H4) =  . Peq(N2) =  . Peq(NH3) =  . Peq(C6H6) =  . (b) Calculate KP for this reaction. KP =  .

A mixture of 0.08069 mol of C2H4, 0.04804 mol of N2, 0.06868 mol of NH3, and 0.1210 mol of C6H6 is placed in a 1.0-L steel pressure vessel at 720 K. The following equilibrium is established: 3 C2H4(g) + 1 N2(g)  2 NH3(g) + 1 C6H6(g) At equilibrium 0.02900 mol of N2 is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C2H4, N2, NH3, and C6H6. Peq(C2H4) =  . Peq(N2) =  . Peq(NH3) =  . Peq(C6H6) =  . (b) Calculate KP for this reaction. KP =  .

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 13CR
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A mixture of 0.08069 mol of C2H4, 0.04804 mol of N2, 0.06868 mol of NH3, and 0.1210 mol of C6H6 is placed in a 1.0-L steel pressure vessel at 720 K. The following equilibrium is established:

3 C2H4(g) + 1 N2(g)  2 NH3(g) + 1 C6H6(g)

At equilibrium 0.02900 mol of N2 is found in the reaction mixture.





(a) Calculate the equilibrium partial pressures of C2H4, N2, NH3, and C6H6.


Peq(C2H4) =  .

Peq(N2) =  .

Peq(NH3) =  .

Peq(C6H6) =  .



(b) Calculate KP for this reaction.


KP =  .

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