A meter stick balances horizontally on a knife-edge at the 50.0 [cm] mark. If you put a stack of 15.0 [g] coins over the 0.100 [m] mark and a stack of 5.0 [g] coins over the 0.750 [m] mark, the stick is found to balance at the 0.45 [m] mark. What is the force exerted by the knife-edge to the meter stick?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
Section: Chapter Questions
Problem 22P: The fishing pole in Figure P10.22 makes an angle of 20.0 with the horizontal. What is the torque...
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A meter stick balances horizontally on a knife-edge at the 50.0 [cm]
mark. If you put a stack of 15.0 [g] coins over the 0.100 [m] mark and a stack of 5.0 [g] coins over the 0.750 [m] mark, the stick is found to balance at the 0.45 [m] mark. What is the force exerted by the knife-edge to the meter stick?
A. 0.735 [N]
B. 0.931 [N]
C. 1.52 [N]
D. 2.55 [N]

Balancing coins. A meter stick balances horizontally on a knife-edge at the 50.0 [cm]
mark. If you put a stack of 15.0 [g] coins over the 0.100 [m] mark and a stack of 5.0 [g]
coins over the 0.750 [m] mark, the stick is found to balance at the 0.45 [m] mark. What is
the force exerted by the knife-edge to the meter stick?
C. 1.52 [N]
D. 2.55 (N]
A. 0.735 [N]
B. 0.931 N]
Transcribed Image Text:Balancing coins. A meter stick balances horizontally on a knife-edge at the 50.0 [cm] mark. If you put a stack of 15.0 [g] coins over the 0.100 [m] mark and a stack of 5.0 [g] coins over the 0.750 [m] mark, the stick is found to balance at the 0.45 [m] mark. What is the force exerted by the knife-edge to the meter stick? C. 1.52 [N] D. 2.55 (N] A. 0.735 [N] B. 0.931 N]
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