A merry-go-round rotates at the rate of 0.17 rev/s with an 90 kg man standing at a point 2.9 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 45 kg cylinder of radius of 2.9 m. Answer in units of rad/s. 024 part 2 What is the change in kinetic energy due to this movement? Answer in units of J. please help

University Physics Volume 1
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Chapter11: Angular Momentum
Section: Chapter Questions
Problem 59P: A bug of mass 0.020 kg is at rest on the edge of a solid cylindrical disk (M=0.10kg,R=0.10m)...
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 A merry-go-round rotates at the rate of 0.17 rev/s with an 90 kg man standing at a point 2.9 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 45 kg cylinder of radius of 2.9 m. Answer in units of rad/s. 024

part 2 What is the change in kinetic energy due to this movement? Answer in units of J.

please help

Expert Solution
Step 1

Given:

initial angular speed  wi = 0.17 rev/smass of man   m = 90kginitial distance from center axis ri =2.9 mmass of merray-go-round  M=45kgRadius R = 2.9 mfinal distance from center axis  rf=0 m

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