A machine cost P1,500,000 and will have a scrap value of P150,000 when retired at the end of 15 years. If money is worth 4.8%, find the annual investment and the capitalized cost of the machine.
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- Machine X has an initial cost of P 45,000, annual maintenance of P 2,250 per year, an no salvage value at the end of its four-year useful life. Machine Y costs P 90,000. The first year there is no maintenance cost. The second year, maintenance is P450, and increases P450 per year in the subsequent years. The machine has an anticipated value P22,500 salvage value at the end of its 12-year useful life.If interest is 8%, what is the present worth of cost of 12 years of Machine X? a) P157,357 b) P140,174 c) P52,452 d) P 119,345Given the two machines' data Machine A Machine B First Cost P8.000.00 P14,000.00 Salvage value 2.000.00 Annual operation 3,000.00 2,400.00 Annual maintenance 1.200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16% Using equivalent uniform annual cost method, determine the value of alternative A and alternative B:Two electric motors to power industrial elevators are being considered. Everyone can reach 100 hp. The relevant data of each engine is as follows: Motor A Motor B Investment P 25,000.00 P 32,000.00 Electrical Efficiency Maintenance per year Life, years 84% 88% 400 600 10 10 The money is worth 20%. If the expected usage time of the hoist is 700 hours per year, what is the cost of electricity required before motor A is better than motor B?
- A machine costs P150,00O and will have a scrap value of P10000 when retired at the end of 15 years. If money is worth 4%, find the annual investment and the capitalized cost of the machine.CB Electronix must buy a piece of equipment to place electronic components on the printed circuit boards it assembles. The proposed equipment has a 10-year life with no scrap value. The supplier has given CB several purchase alternatives. The first is to purchase the equipment for $950,000. The second is to pay for the equipment in 10 equal installments of $125,000 each, starting one year from now. The third is to pay $210,000 now and S85,000 at the end of each year for the next 10 years. Complete parts (a) and (b) below. a. Which alternative should CB choose if its MARR is 11 percent per year? Use an IRR comparison approach. Considering the alternatives in the order of lowest first cost, the best option is the which has an incremental rate of return of %. (Type an integer or decimal rounded to two decimal places as needed. Use an approximate ERR if the IRR cannot be used.)Given the two machines’ data Machine A Machine B First Cost P8,000.00 P14,000.00 Salvage value 0 2,000.00 Annual operation 3,000.00 2,400.00 Annual maintenance 1,200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16% Using equivalent uniform annual cost method, determine the value of alternative A and alternative B: ANSWER for ALTERNATIVE A: Blank 1 ANSWER for ALTERNATIVE B: Blank 2
- A food processing plant consumed 600,000 kW of electric energy annually and pays an average ofP2.00 per kWh. A study is being made to generate its own power to supply the plant the energy required, and that the power plant installed would cost P2,000,000. Annual operation andmaintenance,P800,000. Other expenses P100,000 per year. Life of power plant is 15 years; salvage value at the end of life is P200,000 annual taxes and insurances, 6% of first cost; and rate of interest is 15%. Using the sinking fund method for depreciation, determine if the power plant is justifiable. Compute using the present worth, annual worth, and rate of return.An equipment is bought for $9,000 and sold at the end of its service life for $800. If the service period is 10 years and the MARR is 10%, then the minimum annual savings that this equipment must yield for it to break even is closest to? a) $1,414 b) $1,701 c) $1,312 O d) $1,514You are considering two alternative machines, Machine A and Machine B, for a manufacturing process. One of the machines, Machine A, costs $40,000 to set up and $6,000 per year to operate, but It must be completely replaced every 7 years, and it has no salvage value. Assuming the cost of capital is 8.7%, what is the equivalent annual cost of the machine?
- A certain operation is now performed by hand, the labor cost per unit is P 54 and annual fixed charge for tool use is P 10,000. A machine that is considered for this job will coast P 240,000, and have a salvage value of P 10,000 at the end of its 6 - year life. With it labor cost is P 22 per unit and annual fixed charge is P 20,000. At what number of units per year, at zero interest, will the cost of the two methods break even? Select one: a. 1,150 b. 1,105 c. 1,501 d. 1,510A certain operation is now performed by hand, the labor cost per unit is P 64 and annual fixed charge for tool use is P 10,000. A machine that is considered for this job will coast P 240,000, and have a salvage value of P 10,000 at the end of its 6 - year life. With it labor cost is P 22 per unit and annual fixed charge is P 20,000. At what number of units per year, at zero interest, will the cost of the two methods break even?Given the two machines' data Machine A Machine B First Cost P8,000.00 P14,000.00 Salvage value Annual operation 2,000.00 3,000.00 2,400.00 Annual maintenance 1,200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16% Using equivalent uniform annual cost method,determine the valuejof alternative A and alternative B: