A hydrocarbon of molecular mass 72 g mol–1 gives a single monochloro derivative and two dichloro derivatives on photo chlorination. Give the structure of the hydrocarbon
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A hydrocarbon of molecular mass 72 g mol–1 gives a single monochloro derivative and two dichloro derivatives on photo chlorination. Give the structure of the hydrocarbon
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- Methyl acrylate (H2C=CHCO2CH3) reacts with 1,3-cyclopentadiene to give a mixture of two products. Write structural formulas for both and predict which one predominates.Photochemical chlorination of 2,2,4-trimethylpentane gives four isomeric monochlorides. (a) Write structural formulas for these four isomers. (b) The two primary chlorides make up 65% of the monochloride fraction. Assuming that all the primary hydrogens in 2,2,4-trimethylpentane are equally reactive, estimate the percentage of each of the two primary chlorides in the product mixture.Chlorination of 2-butanone yields two isomeric products, each having the molecular formula C4H7ClO. (a) What are these two compounds? (b) Write structural formulas for the enol intermediates that lead to each of these compounds. (c) Using curved arrows, show the flow of electrons in the reaction of each of the enols with Cl2.
- 2-chloropropane is a major product of the reaction of chlorine with propane under ultraviolet light. Write the mechanism for this reaction including the initiation step and the two propagation steps.An unknown hydrocarbon A with the formula C6H12 reacts with 1 molar equivalent of H2 over a palladium catalyst to give hydrocarbon B. Hydrocarbon A also reacts with OsO4 to give the glycol C. When oxidized with KMnO4 in acidic solution, A gives two fragments. One fragment is propanoic acid, CH3CH2COOH, and the other fragment is ketone D (R2C=O). What are the structures of A, B, C and D? Write all reactions.Write structural formulas for toluene (C6H5CH3) and for benzoic acid (C6H5CO2H) (a) as resonance hybrids of two Kekulé forms and (b) with the Robinson symbol.
- (B). Write the chemical reactions of 2-chloro-2-methylbutane with the following two sets of reagents/experimental conditions given below. In each case, denote the type of the chemical reaction: (i). NaOH/H2O/heat: (ii). NaOH/CH3CH2OH/heat:21.) Calculate the enthalpy of hydrogenation of benzene to cyclohexane from the following reactions A,H (kJ/mol) C6H6 (1) + 15/2 02 (g) → 6 CO2 (g) + 3 H20 (1) C6H12 (1) + 9 02 (g) → 6 CO2 (g) + 6 H20 (1) H2 (g) + ½ 02 (g) → H2O (1) -3268 -3920 -285.83 a.) -205 kJ/mol b.) -1507 kJ/mol c.) -938 kJ/mol d.) -366 kJ/mol(a) Answer the following questions based on the reaction scheme below. Jawab soalan berikut berdasarkan rajah tindak balas di bawah. H,SO, 180°C R OH+ Δ U NH, (i) State reagent Q. Nyatakan reagen Q. (ii) Draw the structural formula for compounds R, T, U and W. Lukiskan formula struktur bagi sebatian R, T, U dan W. PCI,
- Both cis- and trans-2-methylcyclohexanol undergo dehydration in warm sulfuric acid to give 1-methylcyclohexene as the major alkene product. These alcohols can also be converted to alkenes by tosylation using TsCl and pyridine, followed by elimination using KOC(CH3)3 as a strong base. Under these basic conditions, the tosylate of cis-2-methylcyclohexanoleliminates to give mostly 1-methylcyclohexene, but the tosylate of trans-2-methylcyclohexanol eliminates to give only 3-methylcyclohexene. Explain how this stereochemical difference in reactants controls a regiochemical difference in the products of the basic elimination, but not in the acid-catalyzed elimination.A saturated hydrocarbon burns in oxygen to give carbon dioxide and water. Approximately twice as much CO2 as H2O (by weight) is produced by this combustion, the actual factor being 2.03. Light induced chlorination of the hydrocarbon by 2.0 equivalents of chlorine gives a mixture of mono-, di- and trichloro compounds, along with small amounts of higher chlorination products. Only one monochloro isomer is formed, but there are two dichloro isomers and three trichloro isomers produced in the reaction. Based on this information, you should be able to identify the hydrocarbon, and draw structural formulas for the chlorinated compounds.(b) (1-chloromethyl)cyclopentane, CeH11CI reacts with aqueous sodium hydroxide, NaOH to produce a primary alcohol AA. When CeH11Cl is added with magnesium, Mg in ether, an organometallic compound BB is formed. When compound BB reacts with ethanal, CH3CHO, a secondary alcohol cCis formed. The molecular structure of CeH11Cl is given below. (1-klorometil)siklopentana, CoH1,CI bertindak balas dengan akues natrium hidroksida, NaOH bagi menghasilkan satu alkohol primer AA. Apabila CeH11CI ditambah dengan magnesium, Mg dalam eter, sebatian organologam BB terbentuk. Apabila sebatian BB bertindak balas dengan etanal, CH;CHO, satu alkohol sekunder CC dihasilkan. Struktur molekul bagi CsH11CI diberikan di bawah. .CI (1-chloromethyl)cyclopentane (i) Draw the structural formula for compound AA through Cc. Lukiskan formula struktur bagi sebatian AA sehingga C. (ii) What is the type of reaction to produce compound AA? Apakah jenis tindak balas untuk menghasilkan sebatian AA?