A heap's biggest object must be in position 1, while the next-largest item must be in either position 2 or position 3. The locations in a heap of size 31 where the kth largest (i) can appear and (ii) cannot appear, for k=2, 3, and 4 (assuming the numbers are different), should be listed.
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A heap's biggest object must be in position 1, while the next-largest item must be in either position 2 or position 3. The locations in a heap of size 31 where the kth largest (i) can appear and (ii) cannot appear, for k=2, 3, and 4 (assuming the numbers are different), should be listed.
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- Computer Engineering HandsOn Lab: The Government of United States of America has decided to issue new currency notes with special protection features to so as to commemorate a great mathematician. They have decided to issue notes summing up to N and all the sums from 1 to N should only made by selecting some of the notes in only one unique way. With n = 5 the sets {1,1,1,1,1}, {1,2,2}, {1,1,3} are valid. Your task is to design a C++ code that output the solution in one line. Sample Input - 100 Sample Output - 3Tour.java Create a Tour data type that represents the sequence of points visited in a TSP tour. Represent the tour as a circular linked list of nodes, one for each point in the tour. Each Node contains two references: one to the associated Point and the other to the next Node in the tour. Each constructor must take constant time. All instance methods must take time linear (or better) in the number of points currently in the tour. To represent a node, within Tour.java, define a nested class Node: private class Node { private Point p; private Node next; } Your Tour data type must implement the following API. You must not add public methods to the API; however, you may add private instance variables or methods (which are only accessible in the class in which they are declared). public class Tour // Creates an empty tour. public Tour() // Creates the 4-point tour a→b→c→d→a (for debugging). public Tour(Point a, Point b, Point c, Point d) // Returns the number of points in this tour. public…Python Language Q2: Ginormous Campus The campus is pretty big. There are n buildings scattered around it, numbered from 0 to n-1. These buildings are so far away from each other that the only way to get from one to another is to take a campus bus. There are m campus bus routes. The i-th one (0 <= i < m) takes you from building u_i to building v_i (but not the other way around). These buses run very frequently. Professor Zingaro is deciding where to hold his CS lectures. He believes a building x is accessible from a building y if you can get from y to x taking at most two buses. For his students’ convenience, he wants to hold his lectures in the most accessible building. Help him out by telling him how many buildings the most accessible building is accessible from. In addition, list all buildings that are the most accessible. Input The first line of the input contains two space-separated integers n and m, denoting the number of buildings and bus routes, respectively. m lines…
- A Queue is a special array where the insertion and deletion will be via a specific index called "head". A Queue is characterized by 3 attributes: a. capacity (int): the maximum number element Member that can be contained into the Queue; b. head: presents the index where we can add/remove element to the Queue. The head value presents also the current number of elements into the Queue. When a Queue is created the initial value of head is 0; c. Member content[]: an array of elements of type Member; Creates the class Queue with the following methods: a. a Constructor able to create a Queue with maximum 10 Members; b. bool empty (): this method returns true if no element exists in the Queue c. bool full(): this method returns true if there are no place to add a new element to the Queue; d. overload the operator += (Member): able to add an element to the Queue. You need to be sure that there is an available space in the Queue (use the assert function). e. delete(): able to delete an element…C PROGRAMMING Phase 1 Each person eligible to win is placed in one of G groups. For each group, a process is used to narrow down the possible number of winners. The process is as follows:Let a group initially start with p people. We can number the people within a group from 1 to p and assume they are arranged in a circle(circular linked list), with 1, then 2, ..., then p, followed by 1. Each group has its own skip number, s, and its own threshold number, t, where t< p. To eliminate some people in a group from possibility of winning the lottery, start at the person labeled 1 and skip over speople in line. Then, remove the following person. (Thus the first person removed is always person number s+1.)Then repeat the process. Since the line is circular, once you pass the highest numbered person left in line, you'll continue to the lowest numbered person left in line. Continue eliminating people in this fashion until there are precisely t people left. Phase 2 Of all of the people…java program: A linked queue is a single linked list in which: The first node of the linked list is both the front of the queue and the rear of the queue. The first node of the linked list is the rear of the queue and the last node of the linked list is the front of the queue. The first node of the linked list is the front of the queue and the last node of the linked list is the rear of the queue. The last node of the linked list is both the front of the queue and the rear of the queue.
- Use case diagram for "War" Card game . Description of the game: 4 is the max number of players. The deck of cards is split evenly between the players at the beginning of the game, players may shuffle their deck if they wish. The game starts by all the players playing the top of their deck. Whoever has the largest card wins all the cards that were played that turn, and adds them to the bottom of their stack. If two or more players play a card with the same value, those players enter a "war". The players place the next card of their deck face down and then another card face up. Whoever wins the face up card collects all the cards that were played. If the cards happen to be equal again, then another war is done on top of the cards that were already on the table(1st war with 2 players has 4 cards to win, 2nd card with 2 players has 8 cards to win, etc). If a player runs out of cards during a war they immediately lose the game. The game ends when only one player has all the cards. The…⦁ Develop an algorithm that removes the least recently added item from a queue Q. The queue is represented using an array of size s. The algorithm assumes that the queue is not empty. The most recently added item is at index r (rear), and the least recently added item is at index f (front). If the queue is empty, r = f = -1.Maze Runner Function - Implementation of this function is done in a1_partd.py We describe a maze as having row x col cells. For example if row was 3, and col was 4, then we would have a grid of cells as follows. We describe a wall by the two cell numbers the wall separates. If every single wall existed, there would be (row-1)(col) + (col-1)(row) walls. 0 | 1 | 2 | 3 4 | 5 | 6 | 7 8 | 9 | 10 | 11 A Maze class (which you do not need to implement) describes a maze as mentioned above. This class is defined in maze.py. It has methods that you can use to travel through the maze (i.e. figure out where you are, find a neighbour cell etc.) use a recursive maze runner function: def find_path(maze, from_cell, to_cell); The find_path function will find a path from cell number from_cell to cell number to_cell and will return it as a list containing all the cell numbers along the path, from the from_cell to the to_cell. You are allowed to use this function as a wrapper to a recursive function that…
- Exercise # 2 - Detecting Cycle between List of N Airports The following graph is an example from Rosen (2011). It shows the flights and distances between some of the major airports in the United States. Dallas 200 1300 200 Austin Washington Denver 1400 Atlanta 160 800 800 Chicago Houston Write a function that takes a list of N airports and checks if they form a cycle of size N. {A cycle is a directed path that starts and ends at the same vertex. Before writing code, make sure you can identify cycles yourself} >> check_cycles (G, ['Austin','Houston', 'Atlanta','Washington','Dallas'l) Yes >>> check_cycles (G, ['Austin', 'Houston','Atlanta','Washington']) No 600 600 780 0000 000L 006Bishops on a binge def safe_squares_bishops(n, bishops): A generalized n-by-n chessboard has been taken over by some bishops, each represented as a tuple (row, column) of the row and the column of the square the bishop stands on. Same as in the earlier version of this problem with rampaging rooks, the rows and columns are numbered from 0 to n - 1. Unlike a chess rook whose moves are axis-aligned, a chess bishop covers all squares that are on the same diagonal with that bishop arbitrarily far into any of the four diagonal compass directions. Given the board size n and the list of bishops on that board, count the number of safe squares that are not covered by any bishop. To determine whether two squares (r1, c1) and (r2, c2) are reachable from each other in one diagonal move, use abs(r1-r2) == abs(c1-c2) to check whether the horizontal distance between those squares equals their vertical distance, which is both necessary and sufficient for the squares to lie on the same diagonal. This…A chain letter starts with a person sending a letter out to 10 others. Each person is asked to send the letter out to 10 others, and each letter contains a list of the previous six people in the chain. Unless there are fewer than six names in the list, each person sends one dollar to the first person in this list, removes the name of this person from the list, moves up each of the other five names one position, and inserts his or her name at the end of this list. If no person breaks the chain and no one receives more than one letter, how much money will a person in the chain ultimately receive? O 10,000 dollars O 1,000,000 dollars O 500,000 dollars O 100,000 dollars
