A game is played in which each throw of a ball lands in one of two holes: the closer hole or the farther hole. A throw landing in the closer hole scores 2 points, while a throw landing in the farther hole scores 5 points. A player's total score is equal to the sum of the scores on their throws. (c) Tia had t throws that each scored 2 points and f throws that each scored 5 points. If Tia's total score was 37 points, determine all possible ordered pairs (t. f). (c) Since Tia's total score was 37 points, then 2t + 5 f = 37. Since 2t is even for all integer values of t, then 5f must be odd since their sum is 37 (which is odd). The value of 5f is odd exactly when f is odd. When f = 1, we get 2t +5= 37 or 2t = 32, and so t = 16. When f = 3, we get 2t +15=37 or 2t = 22, and so t = 11. When f = 5, we get 2t +25= 37 or 2t 12, and so t = 6. When f = 7, we get 2t +35= 37 or 2t = 2, and so t = 1. When f 29, 5f2 45 and so 2t +5f > 37. The possible ordered pairs (t. f) are (16, 1), (11,3), (6,5), and (1,7).

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter6: Systems Of Linear Equations And Inequalities
Section6.1: Graphing Systems Of Equations
Problem 59PFA
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In the solution  2t+5x>37, why is it >37?

A game is played in which each throw of a ball lands in one of two holes: the closer hole
or the farther hole. A throw landing in the closer hole scores 2 points, while a throw
landing in the farther hole scores 5 points. A player's total score is equal to the sum of
the scores on their throws.
(c) Tia had t throws that each scored 2 points and f throws that each scored 5 points.
If Tia's total score was 37 points, determine all possible ordered pairs (t. f).
(c) Since Tia's total score was 37 points, then 2t + 5 f = 37.
Since 2t is even for all integer values of t, then 5f must be odd since their sum is 37 (which
is odd).
The value of 5f is odd exactly when f is odd.
When f = 1, we get 2t +5= 37 or 2t = 32, and so t = 16.
When f = 3, we get 2t +15=37 or 2t = 22, and so t = 11.
When f = 5, we get 2t +25= 37 or 2t 12, and so t = 6.
When f = 7, we get 2t +35= 37 or 2t = 2, and so t = 1.
When f 29, 5f2 45 and so 2t +5f > 37.
The possible ordered pairs (t. f) are (16, 1), (11,3), (6,5), and (1,7).
Transcribed Image Text:A game is played in which each throw of a ball lands in one of two holes: the closer hole or the farther hole. A throw landing in the closer hole scores 2 points, while a throw landing in the farther hole scores 5 points. A player's total score is equal to the sum of the scores on their throws. (c) Tia had t throws that each scored 2 points and f throws that each scored 5 points. If Tia's total score was 37 points, determine all possible ordered pairs (t. f). (c) Since Tia's total score was 37 points, then 2t + 5 f = 37. Since 2t is even for all integer values of t, then 5f must be odd since their sum is 37 (which is odd). The value of 5f is odd exactly when f is odd. When f = 1, we get 2t +5= 37 or 2t = 32, and so t = 16. When f = 3, we get 2t +15=37 or 2t = 22, and so t = 11. When f = 5, we get 2t +25= 37 or 2t 12, and so t = 6. When f = 7, we get 2t +35= 37 or 2t = 2, and so t = 1. When f 29, 5f2 45 and so 2t +5f > 37. The possible ordered pairs (t. f) are (16, 1), (11,3), (6,5), and (1,7).
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