A fully supported steel bar is described by the parameters listed below. Round your numerical answers in the boxes below to the nearest whole mega-Pascal (MPa) and kilo-Newton (kN) respectively. Don't include the units. E.G. if you get 111,100,000Pa for the stress, write 111. This will be interpreted as 111MPa. If you get 101010 Newtons for the force, write 101. This will be interpreted as 101kN. For the increase in temperature shown, find the normal stress in the bar Given: MPa AND the internal force on a cross section of the bar kN. Round your numerical answers to the nearest whole mega-Pascal (MPa) and kilo-Newton (kN) respectively. Don't include the units. Cross sectional Area of bar = 7900 mm² Temperature Increase = 43 Kelvin Length of bar = 17 m E = 200 GPa alpha=0.0000119 per Kelvin

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter15: Fluids
Section: Chapter Questions
Problem 74PQ
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A fully supported steel bar is described by the parameters listed below.
Round your numerical answers in the boxes below to the nearest whole mega-Pascal (MPa) and kilo-Newton (kN) respectively. Don't include the units.
E.G. if you get 111,100,000Pa for the stress, write 111. This will be interpreted as 111MPa.
If you get 101010 Newtons for the force, write 101. This will be interpreted as 101kN.
For the increase in temperature shown, find the normal stress in the bar
Given:
MPa AND the internal force on a cross section of the bar
kN. Round your numerical answers to the nearest whole mega-Pascal (MPa) and kilo-Newton (kN) respectively. Don't include the units.
Cross sectional Area of bar = 7900 mm²
Temperature Increase= 43 Kelvin
Length of bar = 17 m
E = 200 GPa
alpha= 0.0000119 per Kelvin
Transcribed Image Text:A fully supported steel bar is described by the parameters listed below. Round your numerical answers in the boxes below to the nearest whole mega-Pascal (MPa) and kilo-Newton (kN) respectively. Don't include the units. E.G. if you get 111,100,000Pa for the stress, write 111. This will be interpreted as 111MPa. If you get 101010 Newtons for the force, write 101. This will be interpreted as 101kN. For the increase in temperature shown, find the normal stress in the bar Given: MPa AND the internal force on a cross section of the bar kN. Round your numerical answers to the nearest whole mega-Pascal (MPa) and kilo-Newton (kN) respectively. Don't include the units. Cross sectional Area of bar = 7900 mm² Temperature Increase= 43 Kelvin Length of bar = 17 m E = 200 GPa alpha= 0.0000119 per Kelvin
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