A force of 540 newtons stretches a spring 3 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 10 m/s. Give the initial conditions. x(0) = x'(0) m m/s Find the equation of motion. x(t) m

A force of 540 newtons stretches a spring 3 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 10 m/s. Give the initial conditions. x(0) = x'(0) m m/s Find the equation of motion. x(t) m

Name: A force of 540 newtons stretches a spring 3 meters. A mass of 45 kilo
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Description: A force of 540 newtons stretches a spring 3 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from theequilibrium position with an upward velocity of 10 m/s.Give the initial conditions.x(0) =x'(0)=mm/sFind

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter2: One Dimensional Motion

Section: Chapter Questions

Problem 17PQ: The position of a particle attached to a vertical spring is given by y=(y0cost)j. The y axis points...

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