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A fish swimming in a horizontal plane has velocity V₁ = (4.00 +1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is ₁ = (15.0î - 1.70 ĵ) m. After the fish swims with constant acceleration for 18.0 s, its velocity is = (24.0 î - 6.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? (b) What is the direction of its acceleration with respect to unit vector î? (c) If the fish maintains constant acceleration, where is it at t = 30.0 s? In what direction is it moving? Part 1 of 7 - Conceptualize The fish is speeding up and changing direction in a horizontal plane relative to a known position vector. We will write separate equations to describe the x and y components of its motion under constant acceleration. Part 2 of 7 - Categorize We will model the fish as an object under constant acceleration. We use the standard equations for two dimensional motion in the xy plane. We will use x and y subscripts for the components of position, velocity, and acceleration. We know the initial velocity of the fish and its velocity after a certain period of time. We want to calculate the final position of the fish and its direction of motion after it swims for an additional period of time. Part 3 of 7 - Analyze We are given that at t = 0 s, V₁ = (4.00 Îî + 1.00 ĵ) m/s and ₁ = (15.0 î– 1.70 ĵ) m. After the fish swims for t = 18.0 s, we know that V₁ = (24.0 î - 6.00₁) m/s. (a) Write the x and y components ax and a, for the constant acceleration vector a. 24.0 m/s 1.70 X = Your response differs from the correct answer by more than 10%. Double check your calculations. m/s 18.0 s ay = = Avx At Avy At = m/s² m/s 1.00 m/s 18.0 s m/s²

A fish swimming in a horizontal plane has velocity V₁ = (4.00 +1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is ₁ = (15.0î - 1.70 ĵ) m. After the fish swims with constant acceleration for 18.0 s, its velocity is = (24.0 î - 6.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? (b) What is the direction of its acceleration with respect to unit vector î? (c) If the fish maintains constant acceleration, where is it at t = 30.0 s? In what direction is it moving? Part 1 of 7 - Conceptualize The fish is speeding up and changing direction in a horizontal plane relative to a known position vector. We will write separate equations to describe the x and y components of its motion under constant acceleration. Part 2 of 7 - Categorize We will model the fish as an object under constant acceleration. We use the standard equations for two dimensional motion in the xy plane. We will use x and y subscripts for the components of position, velocity, and acceleration. We know the initial velocity of the fish and its velocity after a certain period of time. We want to calculate the final position of the fish and its direction of motion after it swims for an additional period of time. Part 3 of 7 - Analyze We are given that at t = 0 s, V₁ = (4.00 Îî + 1.00 ĵ) m/s and ₁ = (15.0 î– 1.70 ĵ) m. After the fish swims for t = 18.0 s, we know that V₁ = (24.0 î - 6.00₁) m/s. (a) Write the x and y components ax and a, for the constant acceleration vector a. 24.0 m/s 1.70 X = Your response differs from the correct answer by more than 10%. Double check your calculations. m/s 18.0 s ay = = Avx At Avy At = m/s² m/s 1.00 m/s 18.0 s m/s²

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 11P: A particle moves along the x axis according to the equation x = 2.00 + 3.00t 1.00t2, where x is in...
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A fish swimming in a horizontal plane has velocity (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is ₁ = (15.0 î – 1.70 ĵ) m. After the fish swims with constant acceleration for 18.0 s, its velocity is = (24.0 î – 6.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? (b) What is the direction of its acceleration with respect to unit vector î? (c) If the fish maintains constant acceleration, where is it at t = 30.0 s? In what direction is it moving? Part 1 of 7 - Conceptualize The fish is speeding up and changing direction in a horizontal plane relative to a known position vector. We will write separate equations to describe the x and y components of its motion under constant acceleration. Part 2 of 7 - Categorize We will model the fish as an object under constant acceleration. We use the standard equations for two dimensional motion in the xy plane. We will use x and y subscripts for the components of position, velocity, and acceleration. We know the initial velocity of the fish and its velocity after a certain period of time. We want to calculate the final position of the fish and its direction of motion after it swims for an additional period of time. Part 3 of 7 - Analyze We are given that at t = 0 s, V¡ = (4.00 î + 1.00 ĵ) m/s and ř; = (15.0 î – 1.70 ĵ) m. After the fish swims for t = 18.0 s, we know that V₁ = (24.0 î– 6.00 ĵ) m/s. (a) Write the x and y components ax and a, for the constant acceleration vector a. 24.0 m/s 1.70 X Av. X = Your response differs from the correct answer by more than 10%. Double check your calculations. m/s 18.0 s At a ay = = Δν, = Y = At m/s² 18.0 s m/s² m/s 1.00 m/s -
Transcribed Image Text:A fish swimming in a horizontal plane has velocity (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is ₁ = (15.0 î – 1.70 ĵ) m. After the fish swims with constant acceleration for 18.0 s, its velocity is = (24.0 î – 6.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? (b) What is the direction of its acceleration with respect to unit vector î? (c) If the fish maintains constant acceleration, where is it at t = 30.0 s? In what direction is it moving? Part 1 of 7 - Conceptualize The fish is speeding up and changing direction in a horizontal plane relative to a known position vector. We will write separate equations to describe the x and y components of its motion under constant acceleration. Part 2 of 7 - Categorize We will model the fish as an object under constant acceleration. We use the standard equations for two dimensional motion in the xy plane. We will use x and y subscripts for the components of position, velocity, and acceleration. We know the initial velocity of the fish and its velocity after a certain period of time. We want to calculate the final position of the fish and its direction of motion after it swims for an additional period of time. Part 3 of 7 - Analyze We are given that at t = 0 s, V¡ = (4.00 î + 1.00 ĵ) m/s and ř; = (15.0 î – 1.70 ĵ) m. After the fish swims for t = 18.0 s, we know that V₁ = (24.0 î– 6.00 ĵ) m/s. (a) Write the x and y components ax and a, for the constant acceleration vector a. 24.0 m/s 1.70 X Av. X = Your response differs from the correct answer by more than 10%. Double check your calculations. m/s 18.0 s At a ay = = Δν, = Y = At m/s² 18.0 s m/s² m/s 1.00 m/s -
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