A diesel engine power plant has one 700 kW and two 500 kW generating units. The fuel consumption is 0.28 kg per kWh and the calorific value of fuel oil is 10200 kcal/kg. Find the fuel oil required for a month of 30 days and overall efficiency. Plant capacity factor = 40%.

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter17: Resistive-inductive Series Circuits
Section: Chapter Questions
Problem 3RQ: 3. What is power factor?
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Use calorific value of fuel as 10000 kcal/kg and fuel consumption as 0.25 kg per kWh. Only text work please!! No handwritten.
A diesel engine power plant has one 700 kW and two 500
kW generating units. The fuel consumption is 0.28 kg per
kWh and the calorific value of fuel oil is 10200 kcal/kg.
Find the fuel oil required for a month of 30 days and
overall efficiency.
Plant capacity factor = 40%.
Transcribed Image Text:A diesel engine power plant has one 700 kW and two 500 kW generating units. The fuel consumption is 0.28 kg per kWh and the calorific value of fuel oil is 10200 kcal/kg. Find the fuel oil required for a month of 30 days and overall efficiency. Plant capacity factor = 40%.
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