A deque DQUE is to be implemented using a circular one-dimensional array of size N. Execute procedures to: i) insert and delete elements from DQUE at either end; ii) implement DQUE as an output restricted deque; iii) implement DQUE as an input restricted deque; iv) for the procedures, what are the conditions used for testing whether DQUE is full (DQUE_FULL) and empty (DQUE_EMPTY)?
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A deque DQUE is to be implemented using a circular one-dimensional array of size N. Execute procedures to:
i) insert and delete elements from DQUE at either end;
ii) implement DQUE as an output restricted deque;
iii) implement DQUE as an input restricted deque;
iv) for the procedures, what are the conditions used for testing whether DQUE is full (DQUE_FULL) and empty (DQUE_EMPTY)?
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Solved in 3 steps
- DEQ[0:4] is an output restricted deque implemented as a circular array, andLEFT and RIGHT indicate the ends of the deque, as shown below. INSERT(“xx”,[LEFT | RIGHT]) indicates the insertion of the data item at the left or right end asthe case may be, and DELETE() deletes the item from the left end only.DEQ: LEFT: 2 RIGHT: 5 [1] [2] [3] [4] [5] [6] C1 A4 Y7 N6Execute the following insertions and deletions on DEQ:i) INSERT(“K9”, RIGHT)ii) DELETE()iii) INSERT(“T5”, LEFT)IN C PROGRAMMING LANGUAGE AND COMMENT EVERY LINE PLEASE SO I CAN UNDERSTAND EVERY STEP , The selection sort is one of several techniques for sorting an array. A selection sort compares every element of an array with all the other elements of the array and exchanges their values if they are out of order. After the first pass of a selection sort, the first array element is in the correct position; after the second pass the first two elements of the array are in the correct position, and so on. Thus, after each pass of a selection sort, the unsorted portion of the array contains one less element. Write and test a function that implements this sorting method.In C language, take an Infix expression from the user and apply a check if the user has entered two operators together by mistake. If yes, delete the 2nd operator. Try to work with only one array.
- function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))Create a BST implementation that uses three arrays to represent the BST: a key array, a left and right array indices array, and a right array indices array. The constructor's maximum size should be preallocated to the arrays. Compare your program's effectiveness to that of a typical implementation.Computer Science Done in Perl. Someone gave me a wrong/incomplete answer. Write a function, hashsum, which takes a hash reference as its first argument and an array reference as its second argument. The function should take the elements of the array and use them as keys in the hash. The values in the hash corresponding to the keys in the array should be totaled, and the sum should be returned to the user. If a key passed in the array does not exist in the hash, ignore it. Write a sample program to call this function.
- NORMALIZATION PROBLEM: Normalization is one of the most basic preprocessing techniques in data analytics. This involves centering and scaling process. Centering means subtracting the data from the mean and scaling means dividing with its standard deviation. Mathematically, normalization can be expressed as: X-X 0 In Python, element-wise mean and element-wise standard deviation can be obtained by using .mean() and .std() calls. In this problem, create a random 5 x 5 ndarray and store it to variable X. Normalize X. Save your normalized ndarray as X_normalized.npyIf array A consists only of values of 0, 1, and 2, design a function that sorts A. However, sorting should be done without comparing the records' keys. We approach array A by dividing the area into three places and placing 0, 1, 2 in each place. O goes from index 0, and 2 goes from the largest index. 0 The results before and after alignment are shown below. Before alignment = {0, 1, 1, 0, 1, 2, 1, 2, 0, 0, 0, 1} After alignment = {0, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2}İN C PROGRAMMİNG Write a program that fills an integer array of size 1000 with random positive integers between 1 and 10. Assume that each element represents a different city and the integers stored in the array represent the number of golds in those cities. The program traverses over the array and collects the golds at each city, starting from a random position. When the program visits a certain city, all of the golds are collected, and the visited element of the array becomes 0 (no gold is left at that city.) The journey continues with the rule given below. If the position at the nth step is denoted by pn, and the number of golds at the city pn is denoted by gn, ??+1 ={|(?? +??) ???1000|, ?????2=0. |(?? − ??) ??? 1000|, ????? 2 = 1 The program continues visiting cities until the last three visited city has no gold. The program, at each visit, should print out the following information: • The current city index (pn). • The previous city index (pn-1). • The number of golds at the…
- A spell checker in a word processing program makes suggestions when it finds a word not in the dictionary. To determine what words to suggest, it tries to find similar words. One measure of word similarity is the Levenshtein distance, which measures the number of substitutions, additions, or deletions that are required to change one word into another. For example, the words spit and spot are a distance of 1 apart; changing spit to spot requires one substitution (i for o). Likewise, spit is distance 1 from pit since the change requires one deletion (the s). The word spite is also distance 1 from spit since it requires one addition (the e). The word soot is distance 2 from spit since two substitutions would be required. a. Create a graph using words as vertices, and edges connecting words with a Levenshtein distance of 1. Use the misspelled word “moke” as the center, and try to find at least 10 connected dictionary words. How might a spell checker use this graph? b. Improve the method…You have been given two integer arrays/list(ARR1 and ARR2) of size N and M. respectively. You need to print their intersection; An intersection for this problem can be defined when both the arrays/lists contain a particular value or to put it in other words, when there is a common value that exists in both the arrays/lists. The first line contains an Integer Y which denotes the number of test cases or queries to be run Then the test cases follow. First line of each test case or query contains an integer 'N' representing the size of the first array/list. Second line contains 'N' single space separated integers representing the elements of the first the array/list. Third line contains an integer 'M' representing the size of the second array/list Fourth line contains 'M' single space separated integers representing the elements of the second array/list Output format For each test case print the intersection elements in a row, separated by a single space. Output for every test case will be…IntSet unionWith(const IntSet& otherIntSet) const// Pre: size() + (otherIntSet.subtract(*this)).size() <= MAX_SIZE// Post: An IntSet representing the union of the invoking IntSet// and otherIntSet is returned.// Note: Equivalently (see postcondition of add), the IntSet// returned is one that initially is an exact copy of the// invoking IntSet but subsequently has all elements of// otherIntSet added.// IntSet intersect(const IntSet& otherIntSet) const// Pre: (none)// Post: An IntSet representing the intersection of the invoking// IntSet and otherIntSet is returned.// Note: Equivalently (see postcondition of remove), the IntSet// returned is one that initially is an exact copy of the// invoking IntSet but subsequently has all of its elements// that are not also elements of otherIntSet removed.// IntSet subtract(const IntSet& otherIntSet) const// Pre: (none)//…