A circular footing with a 1.5 m diameter is to be constructed 1.22 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters: Angle of Friction = 250 Nc = 24.1 Nq = 13.1 Ny = 9.1 Cohesion = 48 kN/m2 Unit weight of soil = 20.12 kN/m2 The groundwater table is at a great depth and its effect can be ignored. Determine the following: a) Ultimate bearing Capacity of the soil

A circular footing with a 1.5 m diameter is to be constructed 1.22 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters: Angle of Friction = 250 Nc = 24.1 Nq = 13.1 Ny = 9.1 Cohesion = 48 kN/m2 Unit weight of soil = 20.12 kN/m2 The groundwater table is at a great depth and its effect can be ignored. Determine the following: a) Ultimate bearing Capacity of the soil

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter6: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 6.17P: A 2.0 m 2.0 m square pad footing will be placed in a normally consolidated clay soil to carry a...

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A circular footing with a 1.5 m diameter is to be constructed 1.22 mbelow the ground surface. The subsoil consists of a uniform depositof dense soil having the following strength parameters:Angle of Friction = 25o Nc = 24.1 Nq = 13.1 Ny = 9.1Cohesion = 48 kN/m2Unit weight of soil = 20.12 kN/m2The groundwater table is at a great depth and its effect can beignored.Determine the following:a) Ultimate bearing Capacity of the soilb) Compute the gross allowable bearing capacity of the soil using afactor of safety of 3.c) Compute the total allowable load that the footing can carry.
Calculate the size of a square footing on a soil profile consisting of a medium-densesand layer with constant N values, N60 = 30. The dead load is 500 kN and the live load is200 kN. The footing is embedded 1 m into the sand. Groundwater is 2 m below thesurface. Consider that allwable settlement is 25 mm.
3500 kN 3 m x 3 m 0.6 m Ya = 17.5 kN/m³ Sand 0.6 m GWT Sand Ysat = 18.3 kN/m3 1.2 m Y sat = 17.1 kN/m³ C, = 0.06 Clay 1.2 m e, = 1.4 Cc = 0.38 %3D
1- Given Data Column = 350 Kips = 250 Kips Footing = 3.25 ksi fy la = 60 ksi 40 in x 30 in = 2.7 ksf fy = 60 ksi = 3.25 ksi Find: suitable rectangular footing design for L/B = 1.6. There is no need to determine the development length. 1ksf = 47.5 kPa X= 40 in B Y%3D30 in
A rectangular footing 3m x 2m exerts a pressure of 100kN/m2on a cohesive soil Es= 5x104 kN/m2and µ = 0.5. Estimate the immediatesettlement at the centre, assuming(a) the footing is flexible (b) the footing is rigid (ii) Write about influence of water table in determination of bearing capacity.
The square footing shown in the figure carries a load of 3500 kN. Assume that the stress below the footing is distributed at a slope of 1H:2V. The clay layer is overconsolidated with OCR -2 Q - 3500 kN 4mx Sm 0.6 m Ya - 17.5 kN/m Sand 0.6 m GWT Sand 1.2 m 7'= 8.49 kN/m Yrat = 17.1 kN/m Clay e, = 1.4 C, = 0.06 = 0.38 1.2 m etermine the settlement of the clay layer.
A 1.8 m square, 2 m deep footing supports a service load of 570 kN. It is supported on a clayeysand. A dilatometer test run at the site has returned the following modulus profile.Depth (m) 2 3 4 5 6 7 8 9 10 11 12M (MPa) 7.7 8.8 10.2 14.8 15.4 10.8 11.6 11.6 13.1 13.8 13.4Compute the footing settlement.
3) A circular footing having a diameter of 1.2m has its bottom at a depth of 2.7m from the ground surface. Water table is located at a depth of 1.3m below the ground. Soil has the ff. properties. Dry unit weight = 18.1kn/cum Saturated unit weight = 19.3kn//cum C = 15.74kpa Angle of internal friction = 20deg %3D a) Assuming local shear failure, find ultimate bearing pressure using terzaghi's equation b) Det. Allowable bearing capacity using a factor of safety of 3. c) Find allowable load on footing.
A 3 ft square footing carries a sustained load of 10.6kips. It is placed on the surface of a 30 ft thick saturated overconsolidated clay underlain by dense sand. Based on laboratory tests, the clay can be adequately modeled using the e-log-p method. The laboratory tests provide the following compressibility information for the clay: y = 123.4lb/ft³ Cc = 0.064 1+eo Cr 1+eo Aom = 920lb/ft² The groundwater table is located at the ground surface. Estimate the primary consolidation occurred in the clay layer. Solution: Preliminary Calculations: 1). It should be adequate to compute the compressibility to a depth of = 0.0024 2). Layer thickness = ft; 2). Bearing pressure at the bottom of the footing: q = Primary consolidation for each layer: a). Layer 1: 1). depth to layer midpoint = 2). Total vertical stress at midpoint: Oz ft; 3). Pore water pressure at midpoint: u = 4). Effective vertical stress at minpoint: Oz! 6). Induced vertial stress: Az = = = 9). The type of this layer of soil is :…
2- Determine the stress increase below the center of the footing using both theoretical and approximate methods at the top, middle and bottom of the clay layer. In addition, determine the average stress increase for the clay layer. Dimensions in Heights in m Unit weights in kN/m3 kN m P2 H1 H2 H3 BL Hw 2.5 Yoati 18.0 19.0 3.0 3.0 2.0 16.0 2 3 1174 Load - 0 Hw H1 H2 H3 OSand Clay (hoemally conactiduted)
Calculate the settlement of the 10-ft-thick clay layer that will result from the load carried by a 5-ft-square footing. The clay is normally consolidated. Use the 2:1 method to calculate the average increase of effective pressure in the clay layer. 10 ft 10 ft 10 ft 5 ft ↓ Dry sand Footing size 5 ft x 5ft Sand Clay Ydry = 100 pcf Groundwater table Ysat = 120 pcf Ysat = 110 pcf % = 1.0 LL=40
A footing 3 m x 3 m is supporting a concentric load of 1100 kN. Calculate the settlement in mm of the layer of clay considering the preconsolidation. CHOICES A. 8.37 mm B. 6.12 mm C. 7.28 mm D. 5.56 mm