A circuit consisting of three ideal batteries with voltages 8,E1E2, and 83, and three ideal resistors with resistances R1, R2,R3and R3, is shown in the figure. Calculate the current Ipthrough point P. Let the sign of the current correspond to itsdirection, with "up" being positive.81 = 23.5 V, E2 = 10.5 V, E3 = 30.0 V%3D%3D%3DR1R2R = 1.20 k2, R2 = 14.0 kN, R3 = 6.25 k214.0 kΩ, RE3%3DIp =%3DS TOOLSx10

Given:ε1=23.5 Vε2=10.5 Vε3= 30.0 VR1= 1.20 kΩR2= 14.0 kΩR3= 6.25 kΩ Let the Current I1 passes…

A circuit consisting of three ideal batteries with voltages 81, 81 82, and 83, and three ideal resistors with resistances R1, R2, and R3, is shown in the figure. Calculate the current Ip + R3 82 through point P. Let the sign of the current correspond to its direction, with "up" being positive. • P 8 = 23.5 V, 82 = 10.5 V, 83 = 30.0 V R1 R2 R = 1.20 k2, R2 = 14.0 k2, R3 = 6.25 k2 Ip = mA

A circuit consisting of three ideal batteries with voltages 81, 81 82, and 83, and three ideal resistors with resistances R1, R2, and R3, is shown in the figure. Calculate the current Ip + R3 82 through point P. Let the sign of the current correspond to its direction, with "up" being positive. • P 8 = 23.5 V, 82 = 10.5 V, 83 = 30.0 V R1 R2 R = 1.20 k2, R2 = 14.0 k2, R3 = 6.25 k2 Ip = mA

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter28: Current And Resistance

Section: Chapter Questions

Problem 67PQ

See similar textbooks

Similar questions

A 10.00-meter long wire cable that is made of copper has a resistance of 0.051 ohms, (a) What is the weight if the wire was made of copper? (b) What is the weight of a 10.00-meter-long wire of the same gauge made of aluminum? (c)What is the resistance of the aluminum wire? The density of copper is 8960 kg/m3 and the density of aluminum is 2760 kg/m3.
A circuit consisting of three ideal batteries with voltages ℰ1, ℰ2, and ℰ3, and three ideal resistors with resistances R1,R2, and R3, is shown in the figure. Calculate the current IP through point P. Let the sign of the current correspond to its direction, with "up" being positive. ℰ1=22.0 V, ℰ2=10.5 V, ℰ3=24.0 V ?1=4.30 kΩ, ?2=19.0 kΩ, ?3=7.00 kΩ
A circuit consisting of three ideal batteries with voltages ℰ1, ℰ2, and ℰ3, and three ideal resistors with resistances ?1, ?2, and ?3, is shown in the figure. Calculate the current ?P through point P. Let the sign of the current correspond to its direction, with "up" being positive. ℰ1=32.5 V, ℰ2=12.0 V, ℰ3=24.0 V ?1=2.60 kΩ, ?2=14.0 kΩ, ?3=4.50 kΩ
A circuit consisting of three ideal batteries with voltages 81, E2, and 83, and three ideal resistors with resistances R1, R2, E1 R3 and R3, is shown in the figure. Calculate the current Ip through point P. Let the sign of the current correspond to its direction, with "up" being positive. P 81 = 23.5 V, E2 = 10.5 V, 83 = 30.0 V R1 R2 R = 1.20 k, R2 = = 14.0 k2, R3 = 6.25 kO %3D E3 %3D 0.66 mA Ip = Incorrect
In the schematic below two batteries are in series and drive current through the circuit as shown. The first resistor has a voltage drop AV₁ = 1.2 V, the middle resistor has a resistance of R = 64, and the last resistor has a voltage drop AV₂ = 1 V. Given these parameters, what is the magnitude of current flowing through the circuit in milli-amps (mA)? Giver your answer to 3 significant figures. AV, ww 3.0 V 4.5 V ww ΔV, ww R
Three resistors, R1=80, R2=90, R3=90 are connected to a battery as shown in the figure below. If the battery voltage is 38Volts, determine the power dissipated by R2. Express your answer in units of Watts, using zero decimal places. R2 R1 R3 V
Three resistors, R1=80, R2=20, R3=80 are connected to a battery as shown in the figure below. If the battery voltage is 46Volts, determine the power dissipated by R2. Express your answer in units of Watts, using zero decimal places. R2 ww R1 R3 V
A circuit consisting of three ideal batteries with voltages ℰ1,E1, ℰ2,E2, and ℰ3,E3, and three ideal resistors with resistances ?1,R1, ?2,R2, and ?3,R3, is shown in the figure. Calculate the current ?PIP through point P. Let the sign of the current correspond to its direction, with "up" being positive. ℰ1=16.0 V, ℰ2=15.0 V, ℰ3=27.0 VE1=16.0 V, E2=15.0 V, E3=27.0 V ?1=2.30 kΩ, ?2=22.5 kΩ, ?3=2.25 kΩ
An electric device draws 6.10 AA at 240 VV. If the voltage drops by 25 %, what will be current, assuming nothing else changes? Express your answer to two significant figures and include the appropriate units. I final= If the resistance of the device were reduced by 25 %, what current would be drawn at 240 VV? Express your answer to two significant figures and include the appropriate units. I final=
In the circuit shown in the diagram below, two thick wires connect a 1.7 volt battery to a Nichrome (NiCr) wire. Each thick connecting wire is 17 cm long, and has a radius of 11 mm. The thick wires are made of copper, which has 8.36e+28 mobile electrons per cubic meter, and an electron mobility of 0.00434 (m/s)/(V/m). The Nichrome wire is 8 cm long, and has a radius of 2 mm. Nichrome has 9e+28 mobile electrons per cubic meter, and an electron mobility of 7e-05 (m/s)/(V/m). [Copper What is the magnitude of the electric field in the thick copper wire? ]V/m What is the magnitude of the electric field in the thin Nichrome wire? v/m Nichrome Copper
In the circuit shown in the diagram below, two thick wires connect a 1.5 volt battery to a Nichrome (NiCr) wire. Each thick connecting wire is 17 cm long, and has a radius of 11 mm. The thick wires are made of copper, which has 8.36e+28 mobile electrons per cubic meter, and an electron mobility of 0.00434 (m/s)/(V/m). The Nichrome wire is 8 cm long, and has a radius of 5 mm. Nichrome has 9e+28 mobile electrons per cubic meter, and an electron mobility of 7e-05 (m/s)/(V/m). Copper Copper Nichrome What is the magnitude of the electric field in the thick copper wire? V/m What is the magnitude of the electric field in the thin Nichrome wire? V/m
A circuit consisting of three ideal batteries with voltages 81, 82, and 83, and three ideal resistors with resistances R1, R2, and R3, is shown in the figure. Calculate the current Ip + R3 + 82 through point P. Let the sign of the current correspond to its direction, with "up" being positive. P 81 = 11.5 V, E2 : 18.0 V, 83 24.0 V R1 R2 R1 1.30 kΩ , R 20.5 kΩ, R3 = 3.75 k2 %3D 83 + -0.314 Ip %3D Incorrect