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A chemist was employed to analyse a particular lawn fertiliser, and dissolved 15.0g of the sample in water. Excess barium chloride was added to precipitate all the sulphate as barium sulphate according to the equation: Ba2+(ap)+SO42-(aq)-> BaSO4(s) When the precipitate was filtered, dried and weighed it had a mass of 4.67g. What was the percentage by mass of sulphate in the lawn fert

A chemist was employed to analyse a particular lawn fertiliser, and dissolved 15.0g of the sample in water. Excess barium chloride was added to precipitate all the sulphate as barium sulphate according to the equation: Ba2+(ap)+SO42-(aq)-> BaSO4(s) When the precipitate was filtered, dried and weighed it had a mass of 4.67g. What was the percentage by mass of sulphate in the lawn fert

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter10: Solutions
Section: Chapter Questions
Problem 65QAP: Twenty-five milliliters of a solution (d=1.107g/mL)containing 15.25% by mass of sulfuric acid is...
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4) A chemist was employed to analyse a particular lawn fertiliser, and dissolved 15.0g of the sample in water. Excess barium chloride was added to precipitate all the sulphate as barium sulphate according to the equation:

Ba2+(ap)+SO42-(aq)-> BaSO4(s)

When the precipitate was filtered, dried and weighed it had a mass of 4.67g. What was the percentage by mass of sulphate in the lawn fertiliser?

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