A chemist titrates 110.0 mL of a 0.2187M trimethylamine ((CH3), N) solution with 0.8123 M HCl solution at 25 °C. Calculate the pH at equivalence. The pK, of trimethylamine is 4.19. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCI solution added.

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.149QP: A solution of weak base is titrated to the equivalence point with a strong acid. Which one of the...
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A chemist titrates 110.0 mL of a 0.2187M trimethylamine ((CH3)N)
of trimethylamine is 4.19.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added.
(CH₂) N) solution with 0.8123 M HCl solution at 25 °C. Calculate the pH at equivalence. The p K
Transcribed Image Text:A chemist titrates 110.0 mL of a 0.2187M trimethylamine ((CH3)N) of trimethylamine is 4.19. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added. (CH₂) N) solution with 0.8123 M HCl solution at 25 °C. Calculate the pH at equivalence. The p K
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