A chemist needs 8 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%, 20%, and 50%. How many liters of each solution will satisfy each condition? (a) Use 2 liters of the 50% solution. 10% solution 2 20% solution L (b) Use as little as possible of the 50% solution. 10% solution L 20% solution X L 50% solution X L (c) Use as much as possible of the 50% solution. 10% solution 20% solution 50% solution 3 L

A chemist needs 8 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%, 20%, and 50%. How many liters of each solution will satisfy each condition? (a) Use 2 liters of the 50% solution. 10% solution 2 20% solution L (b) Use as little as possible of the 50% solution. 10% solution L 20% solution X L 50% solution X L (c) Use as much as possible of the 50% solution. 10% solution 20% solution 50% solution 3 L

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter11: Differential Equations

Section11.6: Applications Of Differential Equations

Problem 15E: Solve Exercise 14 if a 25 solution of the same mixture is added instead of pure alcohol.

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