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- An object has a mass of 100 kg.a) How much does it weigh on Earth?b) How much does it weigh on the Moon (gmoon = 1.6 m/sz)?A physicist has just discovered a new kind of particle. The force between two of them is F = –b/r, where r is the distance between the particles. What are the SI units of b? kg/s? kg · m/s? ,2 kg · m?/s? .2 kg · m³/s? .2 kg · m4/s² none of theseweight in pounds is 130, Determine her mass in slugs, from the following answers which of them is correct: * O 40.4 slugs O 4.04 slugs O 13.251 slugs 1275.3 slugs O 44.04 slugs Determine the weight in newton's of a woman whose weight in pounds is 130, from the following answers which of them is correct: * 587 N 687 N 578 N O 1274 N Kkments ef the lamr arm an hmn in the ngarr. The might ef the farunn is Ih wih m anler at Gir he T0 N. Delennine the ambirel mment ahr he dhn piat (a) af tr waths af thr Sin ara and the ere. inm ie falowing asnen which of thon is anet: M= 128.6 Ib.in M= 134 Ib.in M= 107.441 Ib.in O M=0 Ib.in O M=144 Ib.in The laver lumbar reginn A of the spine is the part of che spinal columa mst sIsceptible to abise while rshting escessive bending cased by the meut abat A of a Saree F-KN, Fe sisen valacs of F. - 50cH.ond h - 10 C, determine the a ut al eint A) frm the Saliming Aers which af them is EBETrel.if the aek -o: O M=500 N.m M=500000 N.m M=100000 N.m O M=100 N.m O…
- Substituting, for the coefficient of kinetic friction, we find Xn = 0.25 3 6 m m +); 2 10 (2 451 N/m) ( 0.36 9 ) (25/ 06-6) (CM (ત્ર m m X ney Pi1991 fan of ap by ne anen f S OXTable 3 Applied force 200 N 1 1 Mass, m (kg) (kg-1) Acceleration, a Mass'm 50 0.02 4 100 0.01 2 150 0.0066 1.33 200 0.005 1 220 0.0045 0.91 250 0.004 0.80 300 0.0033 0.67 340 0.0029 0.59 350 0.0028 0.57 380 0.0026 0.53 Illustration VForces Sum of Forces V Values Masses Speed 100 ko 20 ms) Acceleration 053 m/e V Spead Sum of Fore V Acceleration Friction CON Applied Force Applied Force OO 200 Newtons PIET : Forces and Motion Basics Men Fautn AcultiorThe total force on an object is ( 20 ı ^ + 40 ȷ ^ ) Newtons. Its acceleration is ( 4 ı ^ + 6 k ^ ) m/s2. Calculate the object's mass
- A 1.5-kg mass has an acceleration of (4.0i - 3.0j) m/s². Only two forces act on the mass. If one of the forces is (2.0i - 1.4j) N, what is the magnitude of the other force? 4.1 N 07.1 N 5.1 N O24N 6.1 NThe acceleration of an object due to air resistance is a = -bư/m, where v is the %3D speed of the object and m is its mass. What are the SI units of b? O kg/s O kg/s? O kg/m kg/m? O kg - m/s? none of theseThe 100 kg block in the figure takes 5.6 s to reach the floor after being released from rest. (Figure 1) Figure ✓ Part A m m = 100 kg 1 m What is the mass of the block on the left? Express your answer in kilograms. ΠΙ ΑΣΦ ? kg 1 of 1
- 9. Consider the falling object of mass 10 kg in Example 2, but assume now that the drag force is proportional to the square of the velocity. a. If the limiting velocity is 49 m/s (the same as in Example 2), show that the equation of motion can be written as 1 (49² - 1²). 245 dy dt Also see Problem 21 of Section 1.1. b. If y(0) = 0, find an expression for v(t) at any time. Gc. Plot your solution from part b and the solution (26) from Example 2 on the same axes. d. Based on your plots in part c, compare the effect of a quadratic drag force with that of a linear drag force. e. Find the distance x(t) that the object falls in time t. Nf. Find the time T it takes the object to fall 300 m.A student pushes a 12-kg block on a frictionless, horizontal surface. If the block is initially at rest, what is the speed of the block after the student pushes the block for 5 seconds with an acceleration of 2.0 m/s/s? O 2.0 m/s 6.0 m/s 10 m/s 60 m/sObject 1: mass= 0.016300 (kg) weight= (Newtons) distances 1.545 (m) 1.485 (m) 1.375 (m) 1.215 (m) 1.005 (m) t (s) g (m/s²) t (s) g (m/s²) t (s) g (m/s²) t (s) g (m/s²) t (s) g (m/s²) 1 0.56270 0.55116 0.53080 0.49970 0.45360 2 0.56220 0.55028 0.53100 0.49884 0.45470 3 0.56190 0.55030 0.53098 0.49791 0.45428 Mean g (m/s?) Overall Mean g (m/s²):_ Standard Deviation (m/s²): %Error: Trial