A car of mass m = 1150 kg is traveling down a e = 11 degree incline. When the car's speed is vo = 11 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is uz = 0.45. 0+ Otheexpertta.com Calculate the distance the car travels down the hill L in meters until it comes to a stop at the end. L =

A car of mass m = 1150 kg is traveling down a e = 11 degree incline. When the car's speed is vo = 11 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is uz = 0.45. 0+ Otheexpertta.com Calculate the distance the car travels down the hill L in meters until it comes to a stop at the end. L =

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section: Chapter Questions

Problem 8STP

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1 V:IV H.W.docx H.W: Two boxes are connected by a cord running over a pulley. The coefficient of kinetic friction between m, (5kg) and the table is 0.20. We ignore the mass of the cord and pulley and any friction in the pulley, which means we can assume that a force applied to one end of the cord will have the same magnitude at the other end. We wish to find the acceleration, a, of the system, which will have the same magnitude for both boxes assuming the cord doesn't stretch, As m (2Kg) move down, m,move to the right. m. د قوة الشد Tو تسارع النظام .a علما بأن البكرة مهملة الكتلة والاحتكاك؟ 出 1
1 V:IV H.W.docx H.W: Two boxes are connected by a cord running over a pulley. The coefficient of kinetic friction between m, (5kg) and the table is 0.20. We ignore the mass of the cord and pulley and any friction in the pulley, which means we can assume that a force applied to one end of the cord will have the same magnitude at the other end. We wish to find the acceleration, a, of the system, which will have the same magnitude for both boxes assuming the cord doesn't stretch. As m; (2Kg) move down, m, move to the right. m. د قوة الشد Tو تسارع النظام .a علما بأن البكرة مهملة الكتلة والاحتكاك؟ 出 l20 Son la 1
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A book slides across a level, carpeted floor with an initial speed of 3.85 m/s and comes to rest after 3.75 m. Calculate the coefficient of kinetic friction μ between the book and the carpet. Assume the only forces acting on the book are friction, weight. and the normal force. H =
You have devised an experiment to measure the kinetic coefficient of friction between a ramp and a mass. You place the mass on the ramp at an angle high enough that the mass starts sliding. You measure the time it takes to fall down a known distance. The time it takes to fall down the 45 degree ramp starting from a standstill is At = 0.46 sec, m=1 kg, and the distance it falls, Ax , is 0.5 m. What is µk? m Дх in At Uk
You push a box (mass 3 kg) so that its initial speed is 2.2 m/s. It slides across a rough floor (coefficient of kinetic friction 0.48). How far will it slide before it stops? Give your answer in m and report your answer to 2 decimal places.
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A car is moving at 20 m/s along a horizontal road has its brakes suddenly applied and eventually comes to rest. What is the shortest distance in which it can be stopped if the friction coefficient between tires and road is 0.90? Assume that all four wheels brake identically. If the brakes don't lock the car stops via static friction.
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You are driving a car at a constant speed of 14.0 m/s along a straight level road. As you approach anintersection, the stoplight turns red and you slam on breaks and the wheels lock and you skid to a stop in25.0 m. What is the coefficient of kinetic friction between your tires and the road?
A car of mass m = 1100 kg is traveling down a θ = 14 degree incline. When the car's speed is v0 = 13 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is μk = 0.45. Calculate the distance the car travels down the hill L in meters until it comes to a stop at the end