A bowling ball of mass mb = 3.9 kg is rolled down the lane with a velocity of v1 = 2.3 m/s. It strikes a single remaining pin of mass mp = 0.89 kg head on. After the collision the bowling ball has a velocity (in the same direction) of v2 = 1.95 m/s. a) Write an expression for the velocity of the pin in the horizontal direction after the impact, vp. b) What is the pin's speed in m/s? c) Assuming the coefficient of friction is μk = 0.1, how far in meters could the pin slide before stopping if it doesn't topple?

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Description: A bowling ball of mass mb = 3.9 kg is rolled down the lane with a velocity of v1 = 2.3 m/s. It strikes a single remaining pin of mass mp = 0.89 kg head on. After the collision the bowling ball has a velocity (in the same direction) of v2 = 1.95 m/s.

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A bowling ball of mass m_b = 3.9 kg is rolled down the lane with a velocity of v₁ = 2.3 m/s. It strikes a single remaining pin of mass m_p = 0.89 kg head on. After the collision the bowling ball has a velocity (in the same direction) of v₂ = 1.95 m/s.

a) Write an expression for the velocity of the pin in the horizontal direction after the impact, v_p.

b) What is the pin's speed in m/s?

c) Assuming the coefficient of friction is μ_k = 0.1, how far in meters could the pin slide before stopping if it doesn't topple?

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