A block is given an initial velocity of 5.00m/s up a frictionless incline of angle θ=20.0 0. How far up the incline does the block slide before coming to rest?
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A block is given an initial velocity of 5.00m/s up a frictionless incline of angle θ=20.0 0. How far up the incline does the block slide before coming to rest?
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- A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.27 m above the bottom of the chute with an initial speed of 1.07 m/s. The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with a coefficient of kinetic friction of 0.223. How far from the bottom of the chute does the toy zebra come to rest? Assume g = 9.81 m/s2. EA 9.00-kg block is sent up a ramp inclined at an angle 0 = 29.0° from the horizontal. It is given an initial velocity vo = 15.0 m/s up the ramp. Between the block and the ramp, the coefficient of kinetic friction is u = 0.50 and the coefficient of static friction is µ, = 0.70. What distance D along the ramp's surface does the block travel before it comes to a stop? D = m about us privacy policy terms of use contact us help careersA 3.00-kg block is sent up a ramp inclined at an angle 0 = 27.0° from the horizontal. It is given an initial velocity vo = 15.0 m/s up the ramp. Between the block and the ramp, the coefficient of kinetic friction is µ = 0.30 and the coefficient of static friction is µ, = 0.80. What distance D along the ramp's surface does the block travel before it comes to a stop? D =
- A small block slides down a frictionless track whose shape is described by y = (x^2) /d for x<0 and by y = -(x^2)/d for x>0. D = 2.37 m. The block starts at x = 0, and is given a push to the left with an initial speed of 2.76 m/s, so it starts sliding up the track to the left. At what value of x will the block reverse direction and start sliding back down? 0.39 m -0.39 m -0.96 m 0.96 mA boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.49 m above the bottom of the chute with an initial speed of 1.87 m/s. The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with a coefficient of kinetic friction of 0.239. How far from the bottom of the chute does the toy zebra come to rest? Assume g = 9.81 m/s?.A skateboarder with mass m, = 44 kg is standing at the top of a ramp which is h, = 3.9 m above the ground. The skateboarder then jumps on his skateboard and descends down the ramp. His speed at the bottom of the ramp is v= 6.7 m/s. Part (b) The ramp makes an angle e with the ground, where 0= 30°. Write an expression for the magnitude of the friction force, fr. between the ramp and the skateboarder. F;= cos(e) sin(0) 8 9 HOME d 1 2 3 hy m. + END Vf vol BACKSPACE CLEAR Part (c) When the skateboarder reaches the bottom of the ramp, he continues moving with the speed vonto a flat surface covered with grass. The friction between the grass and the skateboarder brings him to a complete stop after 5.00 m. Calculate the magnitude of the friction force, Fgras: in newtons, between the skateboarder and the grass. Fgras:=
- A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.83 m above the bottom of the chute with an initial speed of 1.65 m/s. The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with a coefficient of kinetic friction of 0.203. How far from the bottom of the chute does the toy zebra come to rest? Assume g = 9.81 m/s². 8.9605 m E TOOLS x10 about us privacy policy terms of use help careers contact usA skateboarder with mass m, = 44 kg is standing at the top of a ramp which is h, = 3.9 m above the ground. The skateboarder then jumps on his skateboard and descends down the ramp. His speed at the bottom of the ramp is v= 6.7 m/s. Part (b) The ramp makes an angle e with the ground, where 0 = 30°. Write an expression for the magnitude of the friction force, f, between the ramp and the skateboarder. cos(e) sin(e) 8 HOME a 5 6 1 2 3 h, P . END m, + Vf vol BACKSPACE CLEAR Part (c) When the skateboarder reaches the bottom of the ramp, he continues moving with the speed vfonto a flat surface covered with grass. The friction between the grass and the skateboarder brings him to a complete stop after 5.00 m. Calculate the magnitude of the friction force, Fgras; in newtons, between the skateboarder and the grass. Fgrazs =A 5.20–kg block is set into motion up an inclined plane with an initial speed of vi = 8.20 m/s (see figure below). The block comes to rest after traveling d = 3.00 m along the plane, which is inclined at an angle of θ = 30.0° to the horizontal