A “blink of an eye” is a time interval of about 150 ms for an average adult. The “closure” portion of the blink takes only about 55 ms. Let us model the closure of the upper eyelid as uniform angular acceleration through an angular displacement of 14.0°. What is the value of the angular acceleration the eyelid undergoes while closing?

Principles of Physics: A Calculus-Based Text
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Chapter10: Rotational Motion
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Problem 1P: During a certain time interval, the angular position of a swinging door is described by = 5.00 +...
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A “blink of an eye” is a time interval of about 150 ms for an average adult. The “closure” portion of the blink takes only about 55 ms. Let us model the closure of the upper eyelid as uniform angular acceleration through an angular displacement of 14.0°.

What is the value of the angular acceleration the eyelid undergoes while closing? 

Expert Solution
Step 1

Consider the given data as below.

Time for closure, t=55 ms=0.055 s

Initially eyelids are at rest.

Therefore the initial angular velocity is,

u=0 rads

Angular displacement is,

θ=14°=14×π180 rad=14×3.14180 rad=14×0.0174 rad

θ=0.2436 rad

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