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- What is the percentage of total acid expressed as acetic acid in a sample of vinegar if 4.0g of vinegar requires 29.5ml of 0.153N KOH for an endpoint with phenolphthalein indicator? (molar mass of acetic acid: HC2H3O2 = 60.05g/mol a. 3.995% b. 6.776% c. 8.650% d. 12.68%3 How to Titrate: Lab Techniques Titration Titration Procedures: Add about 100mL of a 0.1 M NAOH solution to a 250mL beaker. 2. Obtain a buret and rinse with about 10 ml of the NaOH solution. 3. Fill the buret with NaOH and record starting volume to the nearest 1m" of a milliliter. 4. Measure out exactly 10.0 ml of HC in a graduated cylinder and add it to a 250mL Erlenmeyer flask along with 1 drop of phenolphthalein indicator. 5. Slowly add the NaOH to the flask with the acid and swirl. Continue adding the base until a color change (faint pink) occurs and remains for at least 10 seconds. This is the endpoint of this neutralization eaction. 6. Read and record the ending volume of NaOH in the buret, 7. Repeat steps 1 through 6 two more times for Trials 2 and 3. 8. Calculate the volume of base added in each trial. 9. Use the volume of base added and the volume of acid added to calculate the molarity of the acid for each trial. 10. Calculate the average molarity of the acid. 11. Calculate…Q: A. A solution is prepared by dissolving 10.2g of glucose, C6H1206 in 405g of water. The final volume of the solution is 414ml. Find the concentration of the solution in units of molality. B. What is the pH of 0.75 M HC2H3O2 solution? Ka= 1.8 x 10-5 and Kw=1.00 x 10-14 HC2H3O2 + H2O + H3O† + C¿H3O21 Atomic weight (H= 1, C=12, O=16) Good Luck
- 10. A 0.514 gram sample of NazCO, (106.0 g/mol) was dissolved in distilled water in a 100.0 mi volumetric flask. The molar concentration of Na,CO, in solution is: 0.0485 M 0.0370 M b. 0.4849 M 0.0340 M 0.0330 M d. е.The solubili dissolves a) Wha 5. A solution is prepared, and contains 0.313 M aqueous sodium cyanide (NaCN). What is the concentration of hydrocyanic acid in the solution at equilibrium? Hydrocyanic acid (HCN) is a weak acid with a Ka = 6.2 x10-10. (8 E1Are you completing this experiment online? Yes Part A Data. Standardization of a Sodium Hydroxide Solution Data Table 1. Measurements for standardization of NaOH Data Table 1. Measurements for standardization of NaOH Trial 1 Trial 2 Trial 3 [1] Tared mass of KHC8H404 (g) 0.335 0.308 0.383 [2] Burette reading of NaOH, initial (mL) 3.75 3.91 4.15 [3] Burette reading of NaOH, final (mL) 19.83 18.14 21.36 Part B Data. Molar Concentration of an Acid Solution Enter the number corresponding to the type of acid you have 1. НА 1 2. H2А 3. НзА
- 1. Find the number of millimoles of solute in a. 226 ?? of 0.320 ? HClO4. b. 25.0 ? of 8.05 ? 10−3 ? K2CrO4. c. 6.00 ? of an aqueous solution that contains 6.75 ??? of AgNO3. d. 537 ?? of 0.0200 ? KOH. 2. Describe the preparation of a. 5.00 ? of 0.0500 ? KMnO4 from the solid reagent. b. 4.00 ? of 0.250 ? HClO4, starting with an 8.00 ? solution of the reagent. c. 400 ?? of a solution that is 0.0250 ? in I2, starting with MgI2. d. 200 ?? of 1.00% (?/?) aqueous CuSO4 from a 0.365 ? CuSO4 solution. e. 1.50 ? of 0.215 ? NaOH from the concentrated commercial reagent [50% NaOH (w/w), ?? ?? = 1.525]. f. 1.50 ? of a solution that is 12.0 ??? in K+, starting with solid K4Fe(CN)6. 3. Exactly 75.00 ?? of a 0.3132 ? solution of Na2SO3 were treated with 150.0 ?? of 0.4025 ? HClO4 and boiled to remove the SO2 formed. a. What was the mass in grams of SO2 that was evolved? b. What was the concentration of the unreacted reagent (Na2SO3 or HClO4) after thereaction was complete?Which one of the equations below represents what happens when HC2H3O2 is dissolved in water? O HC2H3O2+H20 C2H3O2 (aq) + OH (aq) O HC,H;0, + H,0 H;O*(aq) + C,H;02 (aq) O HC2H3O2+ H20 H30(aq) + C2H3O2*(aq) O HC2H;O2+ H20 2H*(aq) + OH (aq) + C2H3O2 (aq) O HC2H3O2+H20 H3O*(aq) + C2H3O2 (aq) eTextbook and Media Save for Later Attempts: 0 of 2 us P Type here to search SC 米 10 to 144 11 トト」 %23 %24 & 3 4 8. Q W R T Y A D G H. J K L V B N M LLA How many mL of 0.40 M NaOH would be fequired to titrate 22.50 mL of 0.250 M H2C2O4 to the equivalence point? The balanced chemical equation has been provided. (3 points) H2C204 (aq) + 2 NaOH (aq) Na2C204 (aq) + 2 H2O (1) 22.50 mL 0.250 M 0.40 M