A 64 KB four-way set-associative cache is byte- addressable and contains 32B lines. Memory addresses are 32b wide. a. Show at least Five main memory block addresses those are mapped to set number 5? b. Find hit/miss for following addresses 01010100011110001100011101000011 (5478C743H) 01010100011110001100011101100011 (5478C763H) 01010100011110001100011101010011 (5478C753H) 01010100011110001100011101001011 (5478C74BH)
Q: t is shown a fully associative cache with four lines. The block size is 8 bytes. What is the memory…
A: Given, Block offset bits = 100 Tag bits = 0001000111011
Q: Consider the following TLB for with 6-bit VPNS and 8-bit PFNS: VPN PFN valid prot 54 184 1wx 42 197…
A: Since 8-bit processor has 8 bit address size and size of page number is 6 bit, hence number of bits…
Q: Suppose that the following direct mapped cache is given, where it is composed of 8 blocks of 4 word…
A: Block size = 4 words So block offset = 2 bits Total # of block inside cache = 8 So index bits = 3…
Q: Consider a 4-way set associative cache made up of 64-bit words. The number of words per line is 8…
A: INTRODUCTION: The cache is a small piece of memory that is part of the CPU and is physically closer…
Q: Find the total bits required for given data size and calculate overhead in percentage: - How many…
A: Direct mapping is the simplest strategy, and it maps every block of memory space into only one…
Q: A Direct mapped cache has a capacity of 16-word cache and a block size of 4 words. Consider the…
A: A Direct mapped cache has a capacity of 16-word cache. block size = 4 words
Q: Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main…
A: Question from cache memory mapping. In this we are talking about set-associative cache mapping. We…
Q: 3. If the virtual address Ox1000 0043 is on physical page Ox42, then what do the following TLB entry…
A: Answer: I have given answered in the handwritten format
Q: A 64 KB four-way set-associative cache is byte addressable and contains 32B lines. Memory addresses…
A: Over here we have given 64KB four-way set-associative cache is byte-addressable and contains 32B…
Q: We are given a list of 64-bit memory address references, given as word addresses. Ox03, Oxb4, Ox2b,…
A:
Q: Given that a 4-way set associative cache memory has 64 KB data and each block contains 32 bytes. The…
A: As per our guidelines, only 3 sub parts will be answered. So, please repost the remaining questions…
Q: A cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory…
A: A 64-bit word means 8 byte.Line size: 8 words in a line, means 8 x 8 bytes = 64 bytes in a line = 26…
Q: A 64 KB four-way set-associative cache is byte- addressable and contains 32B lines. Memory addresses…
A: Given: Memory address= 32 bits Cache Size=64KB = 216 bytes Block size=32 Bytes = 25 bytes 4 way set…
Q: Determine how to split the address (s-r, r, w) for direct mapping.
A: Direct Mapping- Before you go through this article, make sure that you have gone through the…
Q: Consider a cache that stores 32768 KİB of user data with 8-way associativity and a block size of 256…
A: Given question has asked to find the Tag field bits value. Information provided in question are as…
Q: We have a machine with 32 bit addresses. The L1 cache is 4-way set associative and stores 32 blocks.…
A:
Q: Consider a 64K L2 memory and a 4K L1 direct mapped cache with block sizes of 512 values. a. How…
A: L1 cache size = 4 KB = 212 B L2 cache size = 64 KB = 216 B block size = 512 B a) no. of blocks in…
Q: A 3-processor systems implements cache coherence with a snoopy MESI protocol. For each access in the…
A: MESI protocol stands for Modified Exclusive Shared Invalid protocol. it is used for cache coherency.…
Q: Given a computer with a memory system having a40_bit address, a cache consisting of 8192 blocks each…
A: The Answer is
Q: Consider a single-level cache with an access time of 2.5 ns, a line size of 64 bytes, and a hit…
A: Introduction :Given , Single level cache cache access time = 2.5 ns line size = 64 Byte Hit ratio =…
Q: 4. Consider a 64K L2 memory and a 4K L1 4-way associative cache with block sizes of 512. a. How many…
A: Here we calculate the followings terms by using the given information and conclude the answer , so…
Q: Consider a fully-associative cache of size 4. Each slot in the cache can have just one item (i.e.…
A: Fully -associative cache
Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…
A: Given: Goal: Find which block of cache does the address 253 maps to.
Q: pose a computer using direct mapped cache has 4MB of byte-addressable main memor he of 512 blocks,…
A: A) Total number of main memory block = 2^22/2^4 = 2^18 B) Size of offset field = Log(block size) =…
Q: There is a 128 byte, direct-mapped cache where each cache block contains 8 bytes on a 16bit…
A: Answer:-
Q: You are given the following cache: Set Index Tag Valid Byte 0 Byte 1 Byte 2 Byte 3 00 49 6E 76 65 21…
A: Given, Length of memory address = 12 bits E = 2 Block size = 4 byte S = 4
Q: A computer system has a 128 byte cache. It uses four-way set-associative mapping with 8 bytes in…
A: Given Cache size =128 = 27 bytes Block size = 8 bytes = 23 bytes Physical address = 32 bits.…
Q: onsider a direct-mapped cache with 128 blocks. The block size is 32 bytes.…
A: 1 word = 32 bits = 4 bytes Block size = 16 words = 64 bytes a. Number of bits in block offset =…
Q: For a direct-mapped cache with 32KB of data and 8-word blocks. 1. What's the size of tag field if…
A: 1. Block size = 8 words= 8*4=32B Therefore block offset bits = log 32 = 5 bits Total number of block…
Q: consider a 32-bit processor with a 4-way set associative cache, with 1024 total entrie lock size of…
A: Here in this question we have given a 32 bit processors set associative cacche.in which 64 byte…
Q: There is a cache with 8 blocks, find the number of misses for each cache organization…
A: Given: There is a cache with 8 blocks, find the number of misses for each cache organization…
Q: A 64 KB four-way set-associative cache is byte- addressable and contains 32B lines. Memory addresses…
A: (b). The memory address is: Initially, all the cache lines are empty. Each set(0-511) having 4 cache…
Q: Consider a direct mapped cache with 8 cache blocks (0-7). If the memory block requests are in the…
A: I have Provided this answer with full description in step-2.
Q: Assume we have a direct-mapped cache with 64 blocks and each block consists of 16 bytes, the cache…
A: There are a total of 8/16 bytes = 512 rows inthe repository. The repository, therefore, contains 256…
Q: A 64 KB four-way set-associative cache is byte- addressable and contains 32B lines. Memory addresses…
A: As per our guidelines we are allowed to answer only one question at a time. If you want answer of…
Q: Solve the cache problem for Direct Map. Cache holds 64 words, and a block size is 16 words. (5 pts…
A:
Q: pose a computer using fully associative cache has 2MB of byte-addressable main memory and a he of…
A: A) Total number of main memory block = Main memory size /block size = 2^21/2^5 = 2^16 B) Size of…
Q: Consider a fully associative cache with a total of 8 cache blocks (0-7). The main memory block…
A: i) Given 4, 3, 25, 8, 19, 6, 25, 8, 16, 35, 45, 22, 8, 3, 16, 25, 7 So from 0 to 7, we have 4 3 25…
Q: We are given a list of 64-bit memory address references, given as word addresses. Ox03, Oxb4, Ox2b,…
A: Actually, cache is a fast access memory.
Q: Assume we have a direct-mapped cache with 64 blocks and each block consists of 16 bytes, the cache…
A:
Q: Consider a cache of 4 K blocks, a 4 word block size and a 32 bit address main memory. What is the…
A: The total number of tag bits per set for 4-way set associative cache
Q: Consider a small 2-way set associative cache memory, consisting of 4 blocks. For choosing the block…
A: Introduction Given, 2 way set associative cache , block are 4 ,LRU scheme is being used.block…
Q: Consider a cache with 32KIB data, 16-word blocks, and 24-bit addresses, answer the following…
A: cache size C=32KiB(215 Bytes) block size=16 words(25 Bytes) size of main memory =224 number of lines…
Q: We are given a list of 64-bit memory address references, given as word addresses. Ox03, Oxb4, Ox2b,…
A: According to the information given:- We have to identify the binary word address on the basic of…
Q: 3. If the virtual address 0x1000 0043 is on physical page Ox42, then what do the following TLB entry…
A: Answer: I have given answered in the handwritten format
Q: Below is a series of byte addresses in a system with 32 bit words. Assuming a direct-mapped cache…
A: Given byte addresses with 32 bit words, direct mapped cache with 4 word blocks. Total number of…
Q: 1. Suppose we have a 32KB direct-mapped data cache with 32-byte blocks. a) Show how a 32-bit memory…
A: Answer
Q: Consider a direct-mapped cache with 128 blocks. The block size is 32 bytes.…
A: The index for an direct mapped cache is the number of blocks in the cache 2 to the power 6=128. so…
Q: The table below represents 5 lines from a 256 line cache that uses direct mapping with a block size…
A: Here block offset bits is 2 bits since we have 4 words. Also total number of lines is 256 so index…
Q: 6.40 Given the assumptions in Problem 6.38, determine the cache performance of the following code:…
A: A .Now consider the c code given , in which two nested for loop is used . In first nested for loop a…
ans 5 a
Step by step
Solved in 3 steps with 2 images
- A 64 KB four-way set-associative cache is byte addressable and contains 32B lines. Memory addresses are 32b wide. a. Show at least Five main memory block addresses those are mapped to set number 5? b. Find hit/miss for following addresses 01010100011110001100011101000011 (5478C743H) 01010100011110001100011101100011 (5478C763H) 01010100011110001100011101010011 (5478C753H) 01010100011110001100011101001011 (5478C74BH)3. The table below represents five lines from a cache that uses fully associative mapping with a block size of 8. Identify the address of the shaded data, 0xE6, first in binary and then in hexadecimal. The tag numbers and word id bits are in binary, but the content of the cache (the data) is in hexadecimal. Word id bits Tag 000 001 010 011 100 101 110 111 ------------------------------------------ 1011010 10 65 BA 0F C4 19 6E C3 1100101 21 76 CB 80 D5 2A 7F B5 0011011 32 87 DC 91 E6 3B F0 A6 1100000 43 98 ED A2 F7 4C E1 97 1111100 54 9A FE B3 08 5D D2 88A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.
- In a microprocessor of 32 bit addresses, the tag length will change if we design a two-way set-associate cache versus a four-way set-associative cache, with the same number of cache lines in each organization, and the same number of data bytes per set. a. True b. FalseSuppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 bits, the blocks of cache. Suppose also that each block contains 8 bytes. The size of the block offset field is bits, and the size of the tag field is bits. size of the set field isQuestion 18 Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 blocks of cache. Suppose also that each block contains 8 bytes. The size of the block offset field is bits, the bits. size of the set field is bits, and the size of the tag hield is
- Given that a 4-way set associative cache memory has 64 KB data and each block contains 32 bytes. The main memory capacity is 4 GB. a. Find the number of bits for the main memory address. ANSWER: bits b. How many blocks are there in a set? ANSWER: blocks c. How many sets the cache has? ANSWER: d. The main memory address format is => | Tag: e. Which set will be mapped by the main memory address 458195h. ANSWER: sets bits | Set: bits | Word: bits | (in decimal)A computer system has a 128 byte cache. It uses four-way set-associative mapping with 8 bytes in each block. The phy 32 bits, and the smallest addressable unit is 1 byte. (i) To what block frames of the cache can the address 000010AFH be assigned? (ii) If the addresses 000010AFH and FFFF7AXYH can be simultaneously assigned to the same Cache set, what values digits X and Y have?Given that a 4-way set associative cache memory has 64 KB data and each block contains 32 bytes. The main memory capacity is 4 GB. a. Find the number of bits for the main memory address. ANSWER: b. How many blocks are there in a set? ANSWER: c. How many sets the cache has? ANSWER: d. The main memory address format is => | Tag: bits | blocks sets bits | Set: e. Which set will be mapped by the main memory address 458195h. ANSWER: decimal) bits bits | Word: (in
- Given a 4-way set associative cache, which has 256 blocks and 64 bytes per block. Assume a 32-bit address. Calculate the following numbers: Part 1: How many bits are used for the byte offset? Answer = Part 2: How many bits are used for the set index? Answer = bits Answer bits Part 3: How many bits are used for the tag? bitsA cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory size that is cacheable is 1024 Mbits. Assuming 4-way set associative mapping and that the addressing is done at the byte level. What is the format of the main memory addresses (i.e s-d, d, and w)? For the hexadecimal main memory location 2BFACEDH, find the corresponding 4-way set-associative memory formatThe table below shows a 2-way set associative cache. What is the maximum size of the memory in Kbytes? First Way byte offset (binary) 01 Second Way byte offset (binary) Tag (binary) | (8 bits) Index Tag |(8 bits) | Valid Valid 00 10 11 00 01 10 11 000 AF 1 ВС 86 42 19 6D 1 7F B3 74 83 001 25 3B 69 FD 62 3B 1 D2 6C 68 DC 010 DO 1 44 53 23 62 C3 45 38 87 DA 011 15 1 83 13 48 AB 9B 1 41 8E 90 7A 100 DD 1 36 F4 ЕС ЕВ C5 1 7B ЕВ 41 69 101 4A 72 5B EA 8A 1A 34 3B 54 8E 110 8C 1 11 B1 C8 2E 4B 56 52 5B 27 11 55 A6 61 33 4B FO 48 СА А4 2E О а. 16 O b. 64 О с. 32 O d. 10 O e. 4 O f. 1 O g. 2 O h. 8 Clear my choice