A 45.0 mL solution of 0.550 M Pb(NO3)2 was mixed with 50.0 mL of 0.700 M Na3PO4, resulting in the reaction shown below: a) What are the molecular weights of Pb(NO3)2, Na3PO4, Pb3(PO4)2? 3 Pb(NO3)2 (aq) + 2 Na3PO4 (aq) →→→ Pb3(PO4)2 (s) + 6 NaNO3(aq) Pb(NO3)2 331.2 Na3PO4 163.94 Pb3(PO4)2 811.54 Mass: c) Determine the amount of unused reactant in grams. Mass: g/mol b) Determine the theoretical amount of Pb3(PO4)2 (s) formed in grams. g/mol g/mol g g

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
Problem 4.120QE
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A 45.0 mL solution of 0.550 M Pb(NO3)2 was mixed with 50.0 mL of
0.700 M Na3PO4, resulting in the reaction shown below:
a) What are the molecular weights of Pb(NO3)2, Na3PO4, Pb3(PO4)2?
3 Pb(NO3)2 (aq) + 2 Na3PO4 (aq) → Pb3(PO4)2 (s) + 6 NaNO3 (aq)
Pb(NO3)2 331.2
Na3PO4 163.94
Pb3(PO4)2 811.54
Mass:
:
Mass:
:
c) Determine the amount of unused reactant in grams.
g/mol
b) Determine the theoretical amount of Pb3(PO4)2 (s) formed in grams.
g/mol
g/mol
g
09
g
Transcribed Image Text:A 45.0 mL solution of 0.550 M Pb(NO3)2 was mixed with 50.0 mL of 0.700 M Na3PO4, resulting in the reaction shown below: a) What are the molecular weights of Pb(NO3)2, Na3PO4, Pb3(PO4)2? 3 Pb(NO3)2 (aq) + 2 Na3PO4 (aq) → Pb3(PO4)2 (s) + 6 NaNO3 (aq) Pb(NO3)2 331.2 Na3PO4 163.94 Pb3(PO4)2 811.54 Mass: : Mass: : c) Determine the amount of unused reactant in grams. g/mol b) Determine the theoretical amount of Pb3(PO4)2 (s) formed in grams. g/mol g/mol g 09 g
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