A 40 mm diameter aluminum cylinder and 20 mm diameter steel cylinder are positioned snugly between two rigid walls. The temperature is then raised by 30°C. What will be the magnitude of the stress in the aluminum cylinder? Answer in MPa rounded-off to 2 decimal places. Al : E = 72 GPa; a = 22.5 x 10-6/°C L= 80 mm Steel: E = 210 GPa; a = 12 x 10-6/°C L = 200 mm Aluminum Steel

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.2.26P: -26 A rectangular plate of dimensions 125 mm × 75 mm is subjected to tensile stress sy= 67 kPa and...
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A 40 mm diameter aluminum cylinder and 20 mm diameter steel cylinder are
positioned snugly between two rigid walls. The temperature is then raised by
30°C. What will be the magnitude of the stress in the aluminum cylinder?
Answer in MPa rounded-off to 2 decimal places.
Al : E = 72 GPa; a = 22.5 x 10-6/°C L= 80 mm
Steel: E = 210 GPa; a = 12 x 10-6/°C L = 200 mm
Aluminum
Steel
Transcribed Image Text:A 40 mm diameter aluminum cylinder and 20 mm diameter steel cylinder are positioned snugly between two rigid walls. The temperature is then raised by 30°C. What will be the magnitude of the stress in the aluminum cylinder? Answer in MPa rounded-off to 2 decimal places. Al : E = 72 GPa; a = 22.5 x 10-6/°C L= 80 mm Steel: E = 210 GPa; a = 12 x 10-6/°C L = 200 mm Aluminum Steel
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