A 4-bit binary up/down counter is in the binary state of zero. The next state in the DOWNmode is (a) 0001 (b) 1111 (c) 1000 (d) 1110
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- In a 4-bit ripple up-counter how many clock pulses will you apply, starting from state 0 0 0 0, so that the counter outputs are as follows? (a) 0010 (b) 0111 (c) 1001 (d) 1110Below is a 4-bit up-counter. What is the largest number of the counter if the initial state Q 3 Q 2 Q1Q0 =0011? (D 3 an Q 3 are MSB, and when Load = 1 and Count =1 the counter is loaded with the value D 3 ...D0) 4-bit counter Clock Q3 Load Count "I" or Vcc "I" or Vcc Do "1" or Vcc - D, Qi Q2 "0" or Gnd - D2 "0" or Gnd D3 Q3 1111 0011 1100 0110Draw a state diagram for: Mealy state machine to detect the 1010 sequence. The output becomes one when you receive the sequence of 1100 and the output is zero otherwise. Overlap is allowed between the detected sequences.
- Q5/Find the addition result for the following operation (66)8+ (1100)EX-3+(83)10- (F2.1)16 using 2's complement, assume that the result is binary number O 1100000.0001 O 10011111.1111 O None of them O 110000010.111 O 1111101.0001Consider the following runtime stack: BEFORE 00001000 00000006 ESP 00000FFC 00000FF 8 00000FF 4 00000FF0 What would be the value of ESP after pushing the 32-bit value shown below onto the stack? 000000A5 O 00001020 O 00000FF8 O 00000FFC O 000000A5(c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).
- Q1. Show the implementation of 4 bit binary to gray code (shown in below table) converter using either EPROM or PLA. In Gray code only one bit changes at a time. Binary Gray code Decimal equivalent 0000 0000 1 0001 0001 0010 0011 3 0011 0010 4 0100 0110 5 0101 0111 6. 0110 0101 7 0111 0100 8. 1000 1100 1001 1101 10 1010 1111 11 1011 1110 12 1100 1010 13 1101 1011 14 1110 1001 15 1111 1000In the 3-bit counter circuit in the figure, the initial value of the output is set as Y = Y2Y1Y0 = 111. So what is the value of the output Y after the 3 hour mark?The encoder is the inverse operation of a decoder. It generates the binary code corresponding to the input value. The following figure shows a block diagram of 8-to-3 encoder. There are eight inputs, i.e. D7 through D0, and three outputs (binary code), i.e. B2, B1 and B0. Answer the following questions. (Note: You should show all the steps) 1. If the input D7 is high (or “1”) and the other inputs are low (or “0”), what binary code does the encoder generate? 2. Draw the complete truth table of 8-to-3 encoder.
- Q2) Convert to decimal number: 1) The hexadecimal number (FD45) 2) The octal number (7024) 3) The EX-3 (11001010.00110110) 4) The number of base 9 (8301)Design counter that counts from 00 to 59, using the IC 74LS90 ripple counter and use two 7 segment display to display the result count. You can also use 7447 binary to 7-segment Display Decoder. i need the diagram of it-72 in decimal equal to . ..in signed binary O a. 10111000 O b. 10111100 O c. 10111101 O d. 10011100