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A 3.000 L balloon is heated from 3000.0 K to 4000.0 K at a pressure of 1.900 atm. What is the new volume of the balloon ? first: This is a problem a. missing variable b. change in conditions C. 22.414 L/1 mol d. density = molar mass/22.414 L e. partial P second: we need to solve for using the equation f. P g. P1 h. P2 i. V j. V1 (not V) k. V2 (not V) I. n m. n1 (not n) n. n2 (not n) o. T p. T1 (not T) q. T2 (not T) r. R= 8.205 x 10-2 L atm/K mol s. 1 atm = 760 torr t. Ptotal = P1 + P2 + .... u. PV = nRT v. P¡V1 P2V2 ------ ------ finally: The answer is v. 4.000 L w. 2.250 L x. 0.7500 L у. 1.333 L

A 3.000 L balloon is heated from 3000.0 K to 4000.0 K at a pressure of 1.900 atm. What is the new volume of the balloon ? first: This is a problem a. missing variable b. change in conditions C. 22.414 L/1 mol d. density = molar mass/22.414 L e. partial P second: we need to solve for using the equation f. P g. P1 h. P2 i. V j. V1 (not V) k. V2 (not V) I. n m. n1 (not n) n. n2 (not n) o. T p. T1 (not T) q. T2 (not T) r. R= 8.205 x 10-2 L atm/K mol s. 1 atm = 760 torr t. Ptotal = P1 + P2 + .... u. PV = nRT v. P¡V1 P2V2 ------ ------ finally: The answer is v. 4.000 L w. 2.250 L x. 0.7500 L у. 1.333 L

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter5: Gases, Liquids, And Solids
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Problem 5.113P: 5-113 Ammonia and gaseous hydrogen chloride react to form ammonium chloride according to the...
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A 3.000 L balloon is heated from 3000.0 K to 4000.0 K at a pressure of 1.900 atm. What is the new volume of the balloon ? first: This is a problem a. missing variable b. change in conditions C. 22.414 L/1 mol d. density = molar mass/22.414 L e. partial P second: we need to solve for using the equation f. P g. P1 h. P2 i. V j. V1 (not V) k. V2 (not V) I. n m. n1 (not n) n. n2 (not n) О. Т p. T1 (not T) q. T2 (not T) r. R= 8.205 x 10-2 L atm/K mol S. 1 atm = 760 torr t. Ptotal = P1 + P2 + u. PV = nRT v. P¡V1 P2V2 n2T2 finally: The answer is V. 4.000 L w. 2.250 L X. 0.7500 L у. 1.333 L
Transcribed Image Text:A 3.000 L balloon is heated from 3000.0 K to 4000.0 K at a pressure of 1.900 atm. What is the new volume of the balloon ? first: This is a problem a. missing variable b. change in conditions C. 22.414 L/1 mol d. density = molar mass/22.414 L e. partial P second: we need to solve for using the equation f. P g. P1 h. P2 i. V j. V1 (not V) k. V2 (not V) I. n m. n1 (not n) n. n2 (not n) О. Т p. T1 (not T) q. T2 (not T) r. R= 8.205 x 10-2 L atm/K mol S. 1 atm = 760 torr t. Ptotal = P1 + P2 + u. PV = nRT v. P¡V1 P2V2 n2T2 finally: The answer is V. 4.000 L w. 2.250 L X. 0.7500 L у. 1.333 L
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A 3.000 L balloon is heated from 3000.0 K to 4000.0 K at a pressure of 1.900 atm. What is the new volume of the balloon ? first: This is a a. missing variable d. density = molar mass/22.414 L second: we need to solve for o. T 760 torr f. P g. P₁ h. P₂ i. V j. V₁ (not V) n. n₂ (not n) p. T₁ (not T) t. Ptotal = P₁ + P₂ + u. PV = nRT v. P₁V₁ P2V₂ n₁T₁ n₂T2 finally: The answer is w. 0.7500 L problem b. change in conditions x. 1.333 L q. T₂ (not T) e. partial P y. 2.250 L c. 22.414 L/1 mol using the equation k. V₂ (not V) z. 4.000 L I. n r. R = 8.205 x 10-² L atm/K mol m. n₁ (not n) s. 1 atm =
Transcribed Image Text:A 3.000 L balloon is heated from 3000.0 K to 4000.0 K at a pressure of 1.900 atm. What is the new volume of the balloon ? first: This is a a. missing variable d. density = molar mass/22.414 L second: we need to solve for o. T 760 torr f. P g. P₁ h. P₂ i. V j. V₁ (not V) n. n₂ (not n) p. T₁ (not T) t. Ptotal = P₁ + P₂ + u. PV = nRT v. P₁V₁ P2V₂ n₁T₁ n₂T2 finally: The answer is w. 0.7500 L problem b. change in conditions x. 1.333 L q. T₂ (not T) e. partial P y. 2.250 L c. 22.414 L/1 mol using the equation k. V₂ (not V) z. 4.000 L I. n r. R = 8.205 x 10-² L atm/K mol m. n₁ (not n) s. 1 atm =
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