A 23.3 ml sample of vinegar (dilute acetic acid, CH3COOH) is titrated and found to react with 85.2 mL of 0.236 M NaOH. What is the molarity of the acetic acid solution? The balanced reaction is; CH3COOH (aq) + NaOH (aq) → CH3COONa (aq) + H,O (I) Include 2 decimal places in your answer.

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A: Given: Concentration of HClO4 acid = 0.042 M

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A: This can be calculated as:

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A: Titanium (Φ = 6.94 ×× 10–19 J)  Silicon (Φ = 7.77 ×× 10–19 J) λ = 243 nm = 243 x 10-9 m

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A:

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A: This can be calculated as:

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A: Weak acids are partially ionized. % of ionization is very low. for weak acids, Ka = [H+][A-][HA]

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Q: A101.6gram sample of an unknown metal at83.0°C was mixed with318.0grams of 20.1°C water in a…

A: Mass of metal = 101.6 g

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Q: determine the Kb for CN- at 25°C. the Ka for HCN is 4.9 x 10^-10

A: Kb = ? Ka for HCN = 4.9 x 10-10

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