A 2.9-cm-diameter parallel-plate capacitor has a1.5 mm spacing. The electric field strength inside thecapacitor is 9.0x104 V/m.Part AWhat is the potential difference across the capacitor?Express your answer with the appropriate units.▸ View Available Hint(s)AVC-135 VSubmit Previous Answers50Part BCorrectMODEL: The electric potential difference between the plates is determined by the uniform electric field in the parallel-platecapacitor.SOLVE: The potential difference AVc across a capacitor of spacing d is related to the electric field inside byE=AVC AVC=Ed=(9.0 × 10 V/m)(1.5 × 103 m) = 140 VHow much charge is on each plate?Express your answer with the appropriate units.▸ View Available Hint(s)Q- ValueAUnitsSubmit Previous Answers Request AnswerX Incorrect; Try Again; 4 attempts remaining44D-II$%3456789WERTYUо{PDFGHJKLxCvBNMHcommand?xoptionF12]delete

Answered: Image /qna-images/answer/dc5ea98c-ca42-4bb8-9e12-edd9094c3587.jpg

Answered: A 2.9-cm-diameter parallel-plate…

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter8: Capacitance

Section: Chapter Questions

Problem 53P: A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when...

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A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when there is air between the plates. The plates are separated by 2.00 mm. With the charge on the plates kept constant, a dielectric with =5 . is inserted between the plates, completely filling the volume between the plates, (a) What is the potential difference between the plates of the capacitor, before and after the dielectric has been inserted? (b) What is the electrical field at the point midway between the plates before and after the dielectric is inserted?
A spherical capacitor is formed from two concentric spherical conducting spheres separated by vacuum. Tire inner sphere has radius 12.5 cm and the outer sphere has radius 14.8 cm. A potential difference of 120 V is applied to the capacitor, (a) What is the capacitance of the capacitor? tb) What is the magnitude of the electrical field at r = 12.6 cm, just outside the inner sphere? (c) What is the magnitude of the electrical field at r = 14.7 cm, just inside the outer sphere? (d) For a parallel-plate capacitor the electrical field is uniform in the region between the plates, except near the edges of the plates. Is this also true for a spherical capacitor?
Four capacitors are connected as shown in Figure P25.11. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking Vab = 15.0 V. Figure P25.11
(a) Calculate the electric potential 0.250 cm from ail electron, (b) What is the electric potential difference between two points that are 0.250 cm and 0.750 cm from an electron? (c) How would the answers change if the electron were replaced with a proton?
a parallel-plate capacitor with area 0.200 m2 and plate separation of 3.00 mm is connected to a 6.00-V battery. (a) What is the capacitance? (b) How much charge is stored on the plates? (c) What is the electric field between the plates? (d) Find the magnitude of the charge density on each plate. (e) Without disconnecting the battery, the plates are moved farther apart. Qualitatively, what happens to each of the previous answers?
Some cell walls in the human body have a layer of negative charge on the inside surface. Suppose that the surface charge densities are 0.50103C/m2 the cell wall is 5.0109m thick, and the cell wall material has a dielectric constant of = 5.4. (a) Find the magnitude of the electric field in the wall between two charge layers, (b) Find the potential difference between the inside and the outside of the cell. Which is at higher potential? (c) A typical cell in die human body has volume 1016m3 . Estimate the total electrical field energy stored in the wall of a cell of this size when assuming that the cell is spherical. (Hint: Calculate the volume of the cell wall.)
At a certain distance from a charged particle, the magnitude of the electric field is 500 V/m and the electric potential is 3.00 kV. (a) What is the distance to the particle? (b) What is the magnitude of the charge?
(a) Find the electric potential difference Ve required to stop an electron (called a stopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude of electric potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential. Vp/Ve.
The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50 104 V/m. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts. What is the potential 1.00 cm from that plate (and 3.00 cm from the other)?
The surface charge density on a long straight metallic pipe is . What is the electric potential outside and inside the pipe? Assume the pipe has a diameter of 2a.
A parallel-plate capacitor with capacitance C0 stores charge of magnitude Q0 on plates of area A0 separated by distance d0. The potential difference across the plates is V0. If the capacitor is attached to a battery and the charge is doubled to 2Q0, what are the ratios (a) Cnew/C0 and (b) Vnew/V0? A second capacitor is identical to the first capacitor except the plate area is doubled to 2A0. If given a charge of Q0, what are the ratios (c) Cnew/C0 and (d) Vnew/V0? A third capacitor is identical to the first capacitor, except the distance between the plates is doubled to 2d0. If the third capacitor is then given a charge of Q0, what are the ratios (e) Cnew/C0 and (f) Vnew/V0?
The thin, uniformly charged rod shown in Figure P24.41 has a linear charge density . Find an expression for the electric potential at P.

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