A 150 kg table is resting on 60°sloping floor from vertical axis with coefficient of friction u= 0.6 as shown in Figure 4.1. 1.0 m 0.5m 0.2m 0.7 m G 0.6 m 60 Figure 4.1 a) Find the maximum value of the force F, that can be applied without toppling the cabinet. b) Determine the acceleration of the table when the table start to move.
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- The block of weight W is pulled by the force P inclined at the angle to the horizontal. Find the smallest force P and the corresponding angle that would cause impending sliding of the block. The angle of static friction between the block and the ground is s.A block of mass M = 539.0 g sits on a horizontal tabletop. The coefficients of static and kinetic friction are 0.549 and 0.391, respectively, at the contact surface between table and block. The block is pushed on with a 13.6 N external force at an angle \theta with the horizontal. a) What angle with respect to the horizontal will lead to the maximum acceleration in horizontal direction of the block for a given pushing force? (Give your answer in degrees and use the unit "deg") b) What is the value of this maximum horizontal acceleration?In the following diagram, the coefficient of friction between the 1000 N body A and the surface of the table is me = 0.75. Calculate: a) The maximum friction force between block A and the table. b) The maximum weight that block B must have for the entire system to be in balance. or c) The friction force between block A and the table so that the weight of block B can be 80. P-10³ N NR
- The two blocks started at rest. The surface of the inclined plane is frictionless. (note: neglect mass and friction of the pulley) Given: Weight of A=230 lb. Weight of B=300 Ib. Calculate: a) acceleration of A (ft/s"), 30° with the horizontal b) Acceleration of B (ft/s"), downward c) the tension in the cable (Ib.) B 30°Q1) Yousif pushes toward the right on an 11.0 N force on the box in the opposite direction. The magnitude of the kinetic friction force between the box and the very smooth floor is 4.50 N as the box slides toward the right. Also, the magnitude of the normal force is 98 N. For the above information, find the following? a box with a force of magnitude 31.0 N. Sarah applies 6. The free-body diagram 7. The mass of the box 8. The box's acceleration in the x-direction 9. The box's acceleration in the y-direction 10. coefficient of dynamic friction Q 2) A rope pulls the block up the ramp, as shown in the figure. Find the following: 7. Draw a free body diagram for the block. 8. Write the equation that sums the forces on the block that are parallel to the ramp. 9. Write the equation that sums the forces on the block that are perpendicular to the ramp. 10. What is the acceleration of the block perpendicular to the ramp? 11. What is the friction force? a = 4.3 m/s? T = N A = 0.45 6.0 kg 0= 30°…The height of the g point is 0.5m, the distance of the rear wheel to theg point is 1.75m, the distance of the front wheel to the g point is 1.8 m, and the car with a mass of 2100kg brakes suddenly while moving at 24v speed. l-Find the friction coefficient between the wheel and the road? 2-Find the way the vehicle takes until it stops?
- Q2: A A body thrown vertically upward with velocity of 30 m/s. Find the distance it will cover in 4 second. B. A body of weight 200 N is lying on a rough horizontal plane having a coefficient of friction as 0.4. Find the magnitude of the force which can move the body while acting at an angle of 30* with the horizontal as shown in figure. 30 f WA dictionary is pulled to the right at constant velocity by a 10 N force acting 30° upward above the horizontal. The coefficient of kinetic friction between the book and the horizontal surface is 0.5. What is the weight of the book?kihetic friction), f = µN. f is directed opposite to the relative velocity. Example 3.4 Block and Wedge with Friction A block of mass m rests on a fixed wedge of angle 6. The coefficient of friction is u. (For wooden blocks, u is typically in the range of 0.2 to 0.5.) Find the value of 6 at which the block starts to slide, and the acceleration X when it slides. In the absence of friction, the block would slide down the plane; hence the friction force f points up the plane. With the coordinates shown, we have m.X=W sin 6-f and SHOT ON MI A2 MI DUAL CAMERA mỹ = N-W cos 0 2021/4/2 19:27
- Q2: a- Calculate the centripetal force exerted on 900 kg car that negotiates a 500 m radius curve at 25 m/sec. b- Assuming an unbanked curve ,find the minimum statics coefficient of friction between the tires and the road ,statics friction being the reason that keeps the car from slipping.Consider the system shown below. Block A weighs 95.0N and block B weighs55.0N. Once block B is set to downward motion, it descends at a constant speed.A) Calculate the coefficient of kinetic friction between block A and the tabletop.B) A dog, also of weight 95.0N, Falls asleep on top of block A. If block B is now setinto downward motion, what is its acceleration (magnitude and direction)?1. A force of 69N is needed to start an 6.9kg box moving across a horizontal surface. Calculate the coefficient of static friction. If the box continues to move with an acceleration of 1.69 m/s2. What is the coefficient of kinetic friction? 2. A box of 45ON is lying in an inclined plane with angle of 35 degrees. If the applied load to move the box is 269N. Determine the net Ff and the acceleration of the box if the coefficient of static friction is 0.35 and the coefficient of kinetic friction is 0.28.