A 1045 hot-rolled steel tension test specimen has the original diameter and length of 6 mm and 25 mm, respectively. The load and change in length data were recorded as shown in Table 1 below: Table 1. Load and change in length Load (KN) Change in Length Load (KN) Change in Length (mm) (mm)
Q: The following data were obtained during a tension test of a low carbon steel specimen having a gauge…
A: (a) Calculate the stress up to elastic limit. σe=PeA=Peπ4de2=35×103 Nπ40.0016 m2=1.74×1010 N/m2
Q: A 1045 hot-rolled steel tension test specimen has the original diameter and length of 6 mn and 25…
A:
Q: cylindrical specimen of a nickel alloy having an elastic modulus of 207 GPa and an original diameter…
A:
Q: Mild Steel is tested in the laboratory. The data obtained are: Length of Specimen = 320 mm Diameter…
A: Length of Specimen, L = 320 mm = 0.320 m Diameter of Specimen, d = 30 mm = 0.03 m Load, F = 20 kN…
Q: A specimen with cylindrical shape was subjected to tensile test. Please plot the stress vs. strain…
A: Diameter of test specimen, do=11.600 mmLength of test specimen, lo=50.500 mm
Q: 1. A steel of rotating-beam test specimen has an ultimate strength of 1600Mpa. Estimate the life of…
A: Given, Sut = 1600 MPa σrev= 900 MPa From Graph Sut = 1600 MPa = 232 psi => f = 0.77 Sut >…
Q: Experiments were conducted in a tension testing machine to evaluate the material properties of two…
A: Write down the given values using suitable variables. Here d1 signifies 1st-rod diameter, d2…
Q: The following data were collected from a standard 0.505-in. diameter test specimen of a copper alloy…
A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…
Q: In reference to the Tensile Test result for a steel sample shown in the figure below. If the…
A: Given dataDiameter of sample = 12 mmFrom the Force-Elongation graphMaximum force applied =70 kN
Q: 1. Two thick slabs of 300mm each, the first one is used in cold rolling where u=0.08 while the…
A: Since we are allowed to answer one question at a time. We’ll answer the first question since the…
Q: 1. A steel rod is subjected to tension force (diameter: 30 mm) is made of annealed AISI 1015 steel.…
A:
Q: A specimen of steel, 20 mm diameter with a gauge length of 200 mm is tested to destruction. It has…
A: Given, Diameter of the specimen = d = 20 mm Gauge length = l = 200 mm Extension = δl = 0.25 mm…
Q: 02: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile…
A: We are suppose to solve only 3 subparts. Please post other subparts as a separate question.
Q: . In a tensile test of a cylindrical specimen with an initial diameter of 12 mm, the loads at 15 and…
A: Given…
Q: Question 1 Compare the differences between hot and cold rolled steel in terms of their processing…
A:
Q: An machine part is being tested with a load of 63,000 lb. The allowable tensile stress is 10,000…
A: Given : load (P) = 63000 lb allowable tensile stress = 10000 psi factor of safety = 3 original…
Q: A cylindrical specimen of 1018 steel having a diameter of 6.35 mm and a gauge length of 38.1 mm is…
A: The cross-sectional area of the specimen is The stress in the element can be determined as, The…
Q: the stress versus strain diagram, naming axes and units 2) Define modulus of elasticity and…
A: Given L0 = 35 cm = 350 mm Required 1. Stress -strain graph 2. Modulus of elasticity 3. Yield…
Q: 2. Mild Steel is tested in the laboratory. The data obtained are: Length of Specimen = 320 mm/…
A: Given Data: Length of specimen L1=320 mm Diameter of Specimen d=30 mm Load F=20 kN Elongation under…
Q: In a tensile test on a mild steel specimen, the breaking stress as compared to ultimate tensile…
A:
Q: .. An machine part is being tested with a load of 63,000 lb. The allowable tensile stress is 10,000…
A: Given:Allowable Tensile Stress on machine=σmaximum=10000 psi(pound per square…
Q: 2/ Aluminum tensile specimen with 12.5mm diameter, a gauge length of 50.8mm and the final ameter was…
A:
Q: A tensile test is carried out on a bar of a mild steel of diameter 2 cm. the bar yields under a load…
A:
Q: A cold drawn 1144 Stressproof steel specimen with a diameter of 0.874 in. and a 1.0 in. gage length…
A: Given: The diameter of specimen, d = 0.874 in The length of the gage, L = 1.0 in
Q: A specimen with an initial diameter of 12 + b* was tested under tensile conditions and a maximum…
A: Given Data : Maximum loadFmax=60 KN Strain recorded when applied maximum load ε1=65%=65100=0.65…
Q: 85. During a hign cycle fatigue test, a metallic specimen is subjected to cyclic loading with a mean…
A: Given data, σmean= 140 MPa, σmin = 70 MPa
Q: During a high cycle fatigue test, a metallic specimen is subjected to cyclic loading with a mean…
A: Given:σmin=-70 MPaσmean=+140 MPa
Q: 1. A mild steel tensile specimen of initial len tensile test and the following data are obtai Yield…
A:
Q: In a tensile test on a specimen of black mild steel of 12 mm diameter, the followi results were…
A: Given:
Q: Q1-A cylindrical specimen of a aluminum alloy having an elastic modulus of 120 GPa and an original…
A: Let P=Tensile load =4000N E =Elastic modulus =120GPa d =Original diameter =4.2mm L =Maximum Length…
Q: A cylindrical specimen of 1018 steel having a diameter of 6.35 mm and a gauge length of 38.1 mm is…
A:
Q: A rod specimen of ductile cast iron was tested in a torsion-testing machine. The rod diameter was 14…
A:
Q: Tensile test under 40,000 N load was applied to a low carbon steel with a sample diameter of 6 mm.…
A: Given: Tensile load F=40000N Initial diameter Di=6mm Final diameter Df=5mm Solution: a) Engineering…
Q: The relation between maximum utilizable values obtained by tension test and pure shear test for…
A: Maximum shear stress theory is primarily applicable for ductile materials. It is required to…
Q: .From the tensile stress-strain behavior for the brass specimen shown in below, determine the…
A:
Q: To manufacture a piston with a circular cross section, an alloy steel bar is required whose length…
A: Given: Length of piston bar = 35 cm Compression load = 5.2 tons = 5200 kg Factor of safety(FOS) =…
Q: Standard steel specimen of 0.504" diameter elongated 0.0125" in an 8" gage length during a test…
A: for solution refer below images.
Q: 2. A metal alloy has been tested in a tensile test with the following results for the flow curve…
A:
Q: Calculate the maximum stress of a cylindrical specimen of steel alloy having an initial diameter of…
A: Initial diameter of the specimen, d=12.55 mm Length of the specimen, L=110mm Tensile force applied…
Q: A Mild steel specimen of circular cross-section is subjected to tensile test with following data…
A: GivenUltimate laod P=235kNfinal area Af=499mm2initial area Ai=672.8mm2final length Lf=387mminitial…
Q: Force P and length change AL data are given in table below for the initial portion of a tension test…
A: Given Data Di=9.07 mmLi=50.8 mm Value for the stress-strain is shown in above table. Now, The yield…
Q: 02: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile…
A: we are suppose to solve only 3 subparts of a question. please post other parts and other question as…
Q: A mild steel tensile specimen of initial length 44 mm and initial diameter 6.4 mm is subjected to a…
A: Given, l0= 44 mm di = 6.4 mm Yield Strength is = 88 MPa = 88 N/mm2 Fracture Strength is = 152 MPa =…
Q: 2. A tensile test is performed on a bar of Dural (an aluminium alloy) of diameter 15 mm. The bar…
A: Given Data: Diameter of the bar, d=15 mm
Q: • In compression test a greater load is necessary to cause yielding than that required in tension…
A:
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
- 1. A cylindrical specimen of a metal object with a radius of 3.8E-2 m and a gauge length of 20.31 mm is pulled in tension. Use the load-elongation characteristics tabulated below to answer the following questions; Load Length (N) (mm) 20.31 20.38 12 20.45 18 20.51 24 20.55 30 20.61 36 20.64 42.8 20.68 48.9 20.72 55.2 20.76 60 20.79 65.8 20.84 70.7 20.87 77.3 20.93 83.1 20.98 88.6 22.15 91.58 23.24 91.68 25.41 0 6 Change in length Length (x10-2 m) (m) Computed strain Computed stress (N/m²) (a) Compute the cross-sectional area of brass. (3The data illustrated below have been determined while the tension test of the stainless steel sample by amateur engineers. The gage length of the stainless steel sample was 50.8 mm (2.0in.) and, the original diameter of the steel sample was 12.8 mm (0.505in.). Load (Ib) Elongation (in.) Load (Ib) Elongation (in.) 14000 0.020 2 310 0.0022 14400 0.025 4 640 0.0044 14 500 0.060 6950 0.0066 14600 0.080 9 290 0.0088 14800 0.100 11 600 0.0110 14 600 0.120 13000 0.0150 13600 Fracture With the help of Excel, plot the stress-strain diagram for this test conducted, and define the following mechanical properties: a) Young modulus; b) Proportional limit; c) Yield stress @0.2% offset; d) ultimate stress; e) nominal rupture stress.a . Sketch stress strain curve if the result shown in table represent the force and extension happened in steel, and show Mechanical properties that we get from tensile test on curve? (10p)Note : Lo=80 mm , Do=10 mm , use excel to plot the curve ExtensionLoad(mm) (N)0 0.900.83 4694.341.67 4831.412.50 4781.083.33 4918.834.17 4926.585.00 5257.075.83 5437.016.66 5575.888.33 5775.189.16 5847.5210.83 5965.4111.67 6010.5312.50 6042.5713.33 6072.2614.16 6092.9315.00 6113.2416.67 6140.3617.50 6146.3718.33 6148.1419.16 6149.1725.00 5940.2125.83 5675.3326.67 4725.52b. What is meant by modulus of rigidity? if it increases what does happen to material? (2p)
- A tension test was performed on a steel specimen having an original diameter of 0.503 in. and gauge length of 2.00 in. The data is listed in the table below. (Figure 1) Figure Load (kip) Elongation (in.) 0 0 1.50 0.0005 4.60 0.0015 8.00 11.00 11.80 11.80 12.00 16.60 20.00 21.50 19.50 18.50 0.0025 0.0035 0.0050 0.0080 0.0200 0.0400 0.1000 0.2800 0.4000 0.4600 1 of 1 Part A Determine approximately the modulus of elasticity. Express your answer to two significant figures and include the appropriate units. E = Submit ▾ Part B σy = μA Submit Value Request Answer Determine approximately the yield stress. Express your answer to two significant figures and include the appropriate units. μà Value [IMG] ? Request Answer Units Units www. ?Q1- The following data was obtained tensile test ɔn a specimen of 10 mm diameter and gauge length Lo=50 mm: 0 38 | 76.2 92.7 107 149 160.4 | 155 142 124.7 load(KN) | elongation(mm) 0 0.02 0.12 0.25 0.50 2.03 3.55 4.06 5.1 5.84 Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the (ay, ey), (ou , eu), (of,, ef), modulus of elasticity, then detected in the draw ((stroin hardening (m)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region))?A 1045 hot-rolled steel tension test specimen has the original diameter and length of 6 mm and 25 mm, respectively. The load and change in length data were recorded as shown in Table 1 below: Table 1. Load and change in length Load (KN) Change in Length Load (KN) Change in Length (mm) |(mm) 20.56 2.26 2.94 0.01 20.72 3.36 5.58 0.02 20.61 3.83 8.52 0.03 19.97 4.00 11.16 0.04 18.72 Fracture. 12.63 0.05 13.02 0.06 13.16 0.08 13.22 0.10 16.15 0.61 18.50 1.04 20.27 1.80
- Force P and length change AL data are given in table below for the initial portion of a tension test on 7075-T651 Al alloy. The diameter before testing was 9.07 mm., and the gage length Linitial for t length change measurement was 50.8 mm. What tension force is required to cause yielding in a bar of the same material but with a diameter of 20 mm? P, kN AL mm 7.22 0.0839 14.34 0.1636 21.06 26.8 31.7 34.1 35.0 0.241 0.308 0.380 0.484 0.614 36.0 0.924 36.5 1.279 36.9 37.2 1.622 1.9941 - A tensile test is carried out on a specimen of mild steel of gauge length 40 mm and diameter 7.42 mm. The results are: Load (kN) 10 17 25 30 34 37.5 38.5 36 Extension (mm) 0 0.05 0.08 0.11 0.14 0.20 0.40 0.60 0.90 At fracture the final length of the specimen is 40.90 mm. Plot the load/ extension graph and determine (a) The modulus of elasticity for mild steel, (b) The yield stress, (c) The ultimate tensile strength, (d) The percentage elongation 2 - An aluminum alloy specimen of gauge length 75 mm and of diameter 11.28 mm was subjected to a tensile test, with these results: Load (kN) 2.0 6.5 11.5 13.6 16.0 18.0 19.0 20.5 19.0 Extension (mm) 0 0.012 0.039 0.069 0.080 0.107 0.133 0.158 0.225 0.310 The specimen fractured at a load of 19.0 kN. Determine (a) the modulus of elasticity of the alloy, (b) The percentage elongation. (c) The ductility in term of reduction of area (d) Fracture stress (e) Tensile strengthThe following data were obtained during a tension test of an aluminum alloy. The initial diameter of the test specimen was 0.505 in. and the gage length was 2.0 in. Load (lb) -O 2 310 4 640 6 950 9 290 11 600 12 600 Elongation (in.) O 0.00220 0.00440 0.00660 0.00880 0.0110 0.0150 Load (lb) 14 000 14 400 14 500 14 600 14 800 14 600 13 600 Elongation (in.) 0.020 0.025 0.060 0.080 0.100 0.120 Fracture determine the Plot the stress-strain diagram and (a) proportional following mechanical properties: limit; (b) modulus of elasticity; (c) yield point; yield strength at 0.2% offset; and (f) rupture strength. (d) (e) ultimate strength;
- In a tensile test of stainless steel, the following data were obtained: Load (N) 7,200 11,250 13.500 16,200 18.900 Elongation (mm) 0.0 0.505 2.03 5.08 20,200 15.24 20,700 13,200 24.90 10.16 21.80 The dimensions of the cylindrical specimen were initial length L₁ = 50.8 mm and initial arca A₁ - 35.8 mm² and the area at fracture was Ar 10.0 mm². Plot the stress-strain diagram and determine the following: a) Modulus of elasticity b) The yield strength at a strain offset of 0.002 c) Ultimate strength d) Fracture strengthA tension test was performed on a steel specimen having an original diameter of 0.503 in. and gauge length of 2.00 in. The data is listed in the table below. (Figure 1) Figure Load (kip) Elongation (in.) 0 0 1.50 0.0005 4.60 0.0015 8.00 0.0025 11.00 11.80 11.80 12.00 16.60 20.00 21.50 19.50 18.50 0.0035 0.0050 0.0080 0.0200 0.0400 0.1000 0.2800 0.4000 0.4600 1 of 1 Part C Determine approximately the ultimate stress. Express your answer to two significant figures and include the appropriate units. Ju = Submit Part D OR= Submit μÅ Value Request Answer Determine approximately the rupture stress. Express your answer to two significant figures and include the appropriate units. Provide Feedback Value [ID] ? Request Answer Units Units ?Load (N) Elongation (mm) In a tensile test of stainless steel, the following data were obtained: 7,200 11,250 13,500 16,200 18,900 20,200 20,700 13,200 24.90 0.0 0.505 2.03 5.08 10.16 15.24 21.80 The dimensions of the cylindrical specimen were initial length L₁= 50.8 mm and initial area A₁ = 35.8 mm² and the area at fracture was Ar = 10.0 mm². Plot the stress-strain diagram and determine the following: a) Modulus of elasticity b) The yield strength at a strain offset of 0.002 c) Ultimate strength d) Fracture strength