A 0.340 kg particle moves in an xy-plane according to x(t) = -15 + 2t – 4t^3 and y(t) = 25 + 7t –9t^2, with x and y in meters and t in seconds. At t = 0.700 s, what are (a) the magnitude and (b) the angle (relative to the positive direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?

A 0.340 kg particle moves in an xy-plane according to x(t) = -15 + 2t – 4t^3 and y(t) = 25 + 7t –9t^2, with x and y in meters and t in seconds. At t = 0.700 s, what are (a) the magnitude and (b) the angle (relative to the positive direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter5: Newton's Laws Of Motion

Section: Chapter Questions

Problem 23PQ: The x and y coordinates of a 4.00-kg particle moving in the xy plane under the influence of a net...

See similar textbooks

Similar questions

Chapter 05, Problem 010 GO A 0.180 kg particle moves along an x axis according to x(t) = - 14.0 + 2.00 t + 4.00 2- 5.00 t, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.30 s ? Give an expression for the (a) x, (b) y and (c) z components. (a) Number Units (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER powered by MapleNet ere to search 1:51 PM ENG 4/4/2021 ASUS 19home prt sc pause break delete f10 end f1Pgup f12Pgdn insert & 21 4. 8 backspo-
A 3.5 kg particle moves along an x axis according to x(t) = −12 + 5t2 − 4t3, with xin meters and t in seconds. In unit-vector notation, what is the net force acting on theparticle at t = 6 s?
A 0.352 kg particle moves in an xy plane according to x(t) = -11.0+ 1.00 t -5.00 t³ and y(t) = 26.0 +3.00 t - 10.0 t², with x and y in meters and t in seconds. At t = 1.48 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel? (a) Number i (b) Number (c) Number Mo Units Units Units
A particle is subjected to the action of two forces : F1 = 41+ 3 + 6 k [ kN ] and F2 = 51-61 -5k [ kN ] . The coordinate direction angle of the resultant force with the X - axis is
A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, taken as the xy plane. The 5.80-kg puck has a velocity of 1.40î m/s at one instant. Eight seconds later, its velocity is (6.00î + 8.0ĵ) m/s. (a) Assuming the rocket engine exerts a constant horizontal force, find the components of the force. î + ĵ N(b) Find its magnitude. N
The figure shows an overhead view of a 0.026 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F has a magnitude of 3N and is at 8, -31. Force F2 has a magnitude of 10 N and is at 02 = 33". In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity V= (131- 14) m/s, and (c) has the V = (12i – 14i) m/s², where t is time? %3D %3D jUnits (a) Number i i+ jUnits (b) Number (c) Number i+ jUnits
The velocity of a 3.00 kg particle is given by i = (8.00ti + 3.00t? j)m/s, with time t in seconds. At the instant the net force on the particle has a magnitude of 35.0 N, what are the direction (relative to the positive direction of the x axis) of (a) the net force and (b) the particle's direction of travel?
A 3 kg object has a velocity of 3i m/sat one instant. 8 seconds later, its velocity is (5i + 7j) m/s. Assuming the object was subject to a constant Net Force, (a) find the components of the force as well as (b) its magnitude?
A 0.352 kg particle moves in an xy plane according to x(t) = -11.0+ 1.00 t-5.00 t³ and y(t) = 26.0 +3.00 - 10.0 t², with x and y in meters and t in seconds. At t = 1.48 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel? (a) Number i (b) Number i (c) Number i Units Units Units
A 125 kg body sits at rest until 3 forces act up the body: F1 = 24.5 N @ 0o, F2 = 38.0 N @ 160o, and F3 = 44.8 N @ 235o. Determine: (a) The resultant force vector (b) The resultant acceleration vector (c) The velocity vector at 10.0s (d) The position vector at 10.0s
A horizontal line PQRS is 12 m long, where PQ = QR = RS = 4 m. Forces of 1000 N, 1500 N, 1000 N and 500 N act at P, Q, R and S respectively with downward direction. The lines of action of these forces make angles of 90°, 60°, 45° and 30° respectively with PS. Find the magnitude, direction, and position of the resultant force.
The force acting on a particle has a magnitude of 110N and is directed 34.4° above the positive x-axis. (a) Determine the x-component of the force. N (b) Determine the y-component of the force. Need Help? Read It