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9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)²+] was found to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)²+] was found to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section17.5: Precipitation Reactions
Problem 17.12CYU: Solid Pbl2 (Ksp = 9.8 109) is placed in a beaker of water. After a period of time, the lead(II)...
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9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2+] was found to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
Transcribed Image Text:9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2+] was found to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
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