9 Question 10 - Ch 19 HW - Conne X b Answered: Find the pH of the equ b Success Confirmation of Questio G (a) 0.10 M CH3NH2(Kb = 4.4 x 1 X + -> i ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=0&launchUrl=https%253A%252F%252Fnewconnect.mheduc. * Paused Be sure to answer all parts. Find the pH of the two equivalence points and the volume (mL) of 0.0888 M KOH needed to reach them in the titration of 17.3 mL of 0.130 M H2CO3. First equivalent point Second equivalent point mL KOH mL KOH pH pH = 70°F 2:20 PM Sunny 4/24/2022

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter31: Introduction To Analytical Separations
Section: Chapter Questions
Problem 31.17QAP
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Find the pH of the two equivalence points and the volume (mL) of 0.0888 M KOH needed to reach them in the titration of 17.3 mL of 0.130 M H2CO3.
 

 

O Question 10 - Ch 19 HW - Conne X
b Answered: Find the pH of the equ X
b Success Confirmation of Questior X G (a) 0.10 M CH3NH2(Kb = 4.4 × 1 X +
->
i ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=0&launchUrl=https%253A%252F%252Fnewconnect.mheduc. A
C Paused
Be sure to answer all parts.
Find the pH of the two equivalence points and the volume (mL) of 0.0888 M KOH needed to reach them
in the titration of 17.3 mL of 0.130 M H2CO3.
First equivalent point
Second equivalent point
mL KOH
mL KOH
pH
pH =
70°F
2:20 PM
Sunny
4/24/2022
II
Transcribed Image Text:O Question 10 - Ch 19 HW - Conne X b Answered: Find the pH of the equ X b Success Confirmation of Questior X G (a) 0.10 M CH3NH2(Kb = 4.4 × 1 X + -> i ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=0&launchUrl=https%253A%252F%252Fnewconnect.mheduc. A C Paused Be sure to answer all parts. Find the pH of the two equivalence points and the volume (mL) of 0.0888 M KOH needed to reach them in the titration of 17.3 mL of 0.130 M H2CO3. First equivalent point Second equivalent point mL KOH mL KOH pH pH = 70°F 2:20 PM Sunny 4/24/2022 II
O Question 10 - Ch 19 HW - Conne X
b Answered: Find the pH of the equ X
b Success Confirmation of Questior X G (a) 0.10 M CH3NH2(Kb = 4.4 x 10 × +
->
i ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=0&launchUrl=https%253A%252F%252Fnewconnect.mheduc. A
C Paused
This problem involves the titration of a diprotic weak acid with a strong base. The neutralization reactions are:
Soluti
Н-СОЗ(аq) + КОН(аq) — к'"(аq) + НСО; (аq) + Н,0()
Guided So
HCO3 (aq) + KOH(aq) → K"(aq) + CO3² (aq) + H20(1)
The HCO3 and CO3 ions that result from this neutralization undergo hydrolysis as follows:
НСОЗ (ад) + Hә0() — Н-СО3(аq) + ОН (аq)
СОз (аq) + H20() — НСО; (аq) + ОН (аq)
Note: The potassium ion does not undergo hydrolysis and therefore does not impact the pH of the solution.
What are the K, values for H2CO3 and HCO3 ? How would you determine the K, values for HCO3 and
CO3?- from the values of Ka?
70°F
2:18 PM
Sunny
4/24/2022
|D
Transcribed Image Text:O Question 10 - Ch 19 HW - Conne X b Answered: Find the pH of the equ X b Success Confirmation of Questior X G (a) 0.10 M CH3NH2(Kb = 4.4 x 10 × + -> i ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=0&launchUrl=https%253A%252F%252Fnewconnect.mheduc. A C Paused This problem involves the titration of a diprotic weak acid with a strong base. The neutralization reactions are: Soluti Н-СОЗ(аq) + КОН(аq) — к'"(аq) + НСО; (аq) + Н,0() Guided So HCO3 (aq) + KOH(aq) → K"(aq) + CO3² (aq) + H20(1) The HCO3 and CO3 ions that result from this neutralization undergo hydrolysis as follows: НСОЗ (ад) + Hә0() — Н-СО3(аq) + ОН (аq) СОз (аq) + H20() — НСО; (аq) + ОН (аq) Note: The potassium ion does not undergo hydrolysis and therefore does not impact the pH of the solution. What are the K, values for H2CO3 and HCO3 ? How would you determine the K, values for HCO3 and CO3?- from the values of Ka? 70°F 2:18 PM Sunny 4/24/2022 |D
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