9-8. The accompanying figure shows the arrangement of beams and girders that are used to support a 5 in reinforced concrete floor for a small industrial building. Design the beams and girders assuming that they are simply supported. Assume full lateral sup- port of the compression flange and a live load of 80 psf. Concrete weight is 150 lb/ft³. 1 1 Column- -H I H FIGURE P9-8 Beam Girder I 1 3 at 8 ft 24 ft BE -H- H- 30 ft Note: Floor continues on all sides 4-

9-8. The accompanying figure shows the arrangement of beams and girders that are used to support a 5 in reinforced concrete floor for a small industrial building. Design the beams and girders assuming that they are simply supported. Assume full lateral sup- port of the compression flange and a live load of 80 psf. Concrete weight is 150 lb/ft³. 1 1 Column- -H I H FIGURE P9-8 Beam Girder I 1 3 at 8 ft 24 ft BE -H- H- 30 ft Note: Floor continues on all sides 4-

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter10: Plate Girders

Section: Chapter Questions

Problem 10.7.8P

See similar textbooks

Similar questions

4/47 Compute the force in member HN of the loaded truss. BE 2 m A 4/40 n L L D R Q L L F 6 m L P O N -8 panels at 3 m Problem 4/47 age to L BODJEN H M L I L L 2- J [2 m EM K
TASK 3 250 180 14 I 30 24 Weld 450 A compound girder consists of a steel joist with steel plates welded onto each flange as shown. If the ends are simply supported and the effective span is 10 m, what is the maximum UDL which can be supported by the girder? [kN/m] Allowable longitudinal stress in plates = 110 MN/m² Allowable load in shear for each weld = 60 kN/m Allowable shearing stress in web of girder = 75 MN/m² Note: 1.0 MN/m² = 1.0 N/mm² 50
When the columns at E and H of the floor framing plan shown are deleted, girder BEHK becomes one span fixed ended beam supporting beam DEF at E and beam GHI at H.The following loads on girder BEHK are as follows: Concentrated load at E = 277 kN Concentrated load at H = 266 kN Uniform load throughout its length = 8 kN/m 2.5 m 2.0 m 2.0 m A D G 6m B E H K 6m C F Calculate the maximum positive moment (kN.m) due to the uniformly distributed load only. (TWO DECIMAL PLACES)
Given: Consider the floor frame below supports a 6-in. concrete floor. Assume the beams and girders have full lateral support of the compression flange throughout the entire length. The floor live load is 120psf and assume concrete density is 150 pct. Column I Beam Girder 3 @15ft = 45ft I Find: The lightest W-shape beam and girder. LRFD and ASD 38 ft ✈ Copyright 2012 Peanon Education puting as Petice Hall Note: Floor continues on all sides
A. A truss member is made with a pair of 4"x 3" x 3/8" angles with the long legs back to back. The angles are 36 ksi steel and are attached at the connection by a 3/8 in. plate running between the angles. The unbraced length is 12 feet and consider both ends fixed. What is the allowable axial load in compression? In tension? How does the compression capacity change if I connect them with a %" plate in between? Does it change tension capacity? (a) 12 C. A 28 foot column is braced top and bottom about the X-X axis and has K bracing as shown on the Y-Y axis only. It is built of A36 steel and is a W12 x 30 section. Can it support an axial load of 165 kips? State its actual capacity.
The floor structural system shown in Fig 1 comprise W-section steel beams and girders supporting a 5-inch thick concrete slab which provides full restraint to the flanges of the beams. The density of concrete is 150 lbs. /ft³. and the uniformly distributed live load L=50 lbs/ft². L-22¹ B B. Girder G1: - [82] 12' Gl GI [BI] FIG. 1-Steel Floor Beam a) Strength - Bending and Shear 12' + I 1) Produce a sketch of the floor plan showing the tributary load distribution areas for the beams and girders [zul
ure B 2m2 m C -2 m D 4 m 500 N 700 N 2 of 2 Part B Identify the zero-force members in the truss shown in (Figure 2). Check all that apply. 000 CD DE CG CF FG BC BG DF AG EF AB Submit Provide Feedback Request Answer
your A Doparmment of Civl Engineeng College of Engneeing hversity of Minan Instructor. Dr. Murtada Abass Example 2 of Method of Sections: Determine the force in member EB of the FBD of the roof truss shown in the Figure below. Indicate the member in compression (C) or in tension (T). 1000 N 3000 N 1000 N 1000 N B -2 m -2 m- 2 m 4000 N 2000 N (a)
The given girder has beams framing into it at the ends and at every L/3 point. The beam carries a service live load of 20 kips as shown and superimposed uniformly distributed service dead load of 10 kip/ft. Select the lightest A992 W-section that can carry the load. Do not check for deflection. P, = 20 kips LL PLL W. = 10 kip/ft DL = 20 ft WDL L/3 BEAMS FRAMING INTO GIRDER L
The double web girder is constructed from two plywood sheets that are secured to wood members at its top and bottom. Each fastener can support 60lb in single shear. Determine the required spacing, s, of the fasteners needed to support the loading of 2800lb. Assume A is pinned and B is a roller.
An 80-foot long plate girder (see below) is fabricated from a ½-inch x 78-inch web and two 3inch x 22-inch flanges. Continuous lateral support is provided. The steel is A992. The loading consists of a uniform service dead load of 1.0 kip/ft (including the self-weight), a uniform service live load of 2.0 kips/ft, and a concentrated service live load of 500 kips at midspan. Stiffeners are placed at each end and at 4 feet, 16 feet, and 28 feet from each end. Once stiffener is placed at midspan. Determine whether the flexural strength is adequate using LRFD.
A plate girder must be designed for the conditions shown in Figure P10.7-4. The given loads are factored, and the uniformly distributed load includes a conservative estimate of the girder weight. Lateral support is provided at the ands and at the load points. Use LRFD for that following: a. Select the, flange and web dimensions so that intermediate stiffeners will he required. Use Fy=50 ksi and a total depth of 50 inches. Bearing stiffeners will be used at the ends and at the load points, but do not proportion them. b. Determine the locations of the intermediate stiffeners, but do not proportion them.