8. If w is TRUE, x is TRUE, andy is FALSE, what is ((w AND X AND y') OR (W' AND X AND y')) AND ((w AND X AND y') AND (w' AND X AND y'))' ? TRUE Not enough information. FALSE NULL
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- Mutliple choice. A. National good will always be a communal good. B. Not all communal good are national good a. If statement B is correct b. Both statements are correct c. Neither A nor B is correct d. If statement A is correctLet M(x) = "x passed the midterm". Let F(x) = "x passed the final". Select the statement below which means: "If nobody passed the midterm, then everyone passed the final". Vx-M(x)→ VxF(x) Vx(M(x)→ F(x)). +VæM(z) → VF(x) Vx(-M(x) → F(x))12. If w is TRUE, x is TRUE, and y is FALSE, what is [((w OR X) AND (x AND y¹)) OR ((w OR x) AND (w' or y'))] AND ((x AND y') AND (w' or y'))' ? Not enough information. TRUE NULL FALSE
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- If w is TRUE, x is TRUE, and y is FALSE, what is ((w AND x AND y') OR (w' AND x AND y')) AND ((w AND x AND y') AND (w' AND x AND y'))'?A (A vq) is a Select one: O a. all of the mentioned O b. non of the mentioned O c. Contingency d. Tautology O e. ContradictionFour mathematicians have a conversation, as follows: ALICE: I am insane. BOB: I am pure. CHARLES: I am applied. DOROTHY: I am sane. ALICE: Charles is pure. BOB: Dorothy is insane. CHARLES: Bob is applied. DOROTHY: Charles is sane. You are also given the following information: Pure mathematicians tell the truth about their beliefs. Applied mathematicians lie about their beliefs. Sane mathematicians' beliefs are correct. Insane mathematicians' beliefs are incorrect. With the preceding clues, classify the four mathematicians as applied or pure, and insane or sane. Briefly explain your logic.
- Correct code answer with output screenshot. Else downvoted. William is facilitating a get-together for n of his broker companions. They began a conversation on different monetary forms they exchange, however there's an issue: not all of his dealer companions like each cash. They like a few monetary standards, yet not others. For each William's companion I it is known whether he enjoys money j. There are m monetary standards altogether. It is likewise realized that a merchant dislike more than p monetary forms. Since companions need to have some normal subject for conversations they need to track down the biggest via cardinality (perhaps vacant) subset of monetary standards, with the end goal that there are essentially ⌈n2⌉ companions (gathered together) who like every money in this subset. Input The primary line contains three integers n,m and p (1≤n≤2⋅105,1≤p≤m≤60,1≤p≤15), which is the number of broker companions, the number of monetary forms, the greatest number of…Thank you! Transitive is failing for these cases. Do you have any advice? (transitive? '((a . b) (b . c) (a . c) (b . d) (a . d) (j . k) (j . l) (k . l)) (transitive? '((a . a) (b . b) (c . d)))(transitive? '((a . c) (a . b) (b . c) (j . k) (k . j) (j . j) (k . k)))please answer with proper explanation for right and wrong both options.